How can I use the Twitter Search API to return all tweets that match my search query, posted only within the last five seconds?

匿名 (未验证) 提交于 2019-12-03 02:49:01

问题:

I would like to use the API to return all tweets that match my search query, but only tweets posted within the last five seconds.

With Twitter's Search API, I can use the since_id to grab all tweets from a specific ID. However, I can't really see a good way to find the tweet ID to begin from.

I'm also aware that you can use "since:" in the actual query to use a date, but you cannot enter a time.

Can someone with Twitter API experience offer me any advice? Thanks for reading and your time!

http://apiwiki.twitter.com/Search-API-Documentation

回答1:

This sounds like something you can do on your end, as created_at is one of the fields returned in the result set. Just do your query, and only use the ones that are within the last 5 seconds.



回答2:

        <script type="text/javascript" charset="utf-8">     // JavaScript Document     $(document).ready(function(){      // start twitter API         $.getJSON('http://twitter.com/status/user_timeline/YOUR_NAME.json?count=10&callback=?', function(data){         $.each(data, function(index, item){             $('#twitter').append('<div class="tweet"><p>' + item.text.linkify() + '</p><p><strong>' + relative_time(item.created_at) + '</strong></p></div>');         });      });       function relative_time(time_value) {       var values = time_value.split(" ");       time_value = values[1] + " " + values[2] + ", " + values[5] + " " + values[3];       var parsed_date = Date.parse(time_value);       var relative_to = (arguments.length > 1) ? arguments[1] : new Date();       var delta = parseInt((relative_to.getTime() - parsed_date) / 1000);       delta = delta + (relative_to.getTimezoneOffset() * 60);        var r = '';       if (delta < 60) {         r = 'a minute ago';       } else if(delta < 120) {         r = 'couple of minutes ago';       } else if(delta < (45*60)) {         r = (parseInt(delta / 60)).toString() + ' minutes ago';       } else if(delta < (90*60)) {         r = 'an hour ago';       } else if(delta < (24*60*60)) {         r = '' + (parseInt(delta / 3600)).toString() + ' hours ago';       } else if(delta < (48*60*60)) {         r = '1 day ago';       } else {         r = (parseInt(delta / 86400)).toString() + ' days ago';       }        return r;     }      String.prototype.linkify = function() {         return this.replace(/[A-Za-z]+:\/\/[A-Za-z0-9-_]+\.[A-Za-z0-9-_:%&\?\/.=]+/, function(m) {             return m.link(m);         });     };// end twitter API     }); // ***** end functions *****     </script>             <div id="twitter">     Target Div                            </div> 


回答3:

Are you trying to poll tweets in real time? Doesn't twitter have a limit on API req/hour. I think you'd hit that pretty fast.



回答4:

Why don't you just make a call to the API every 5 seconds and grab the top 1 tweet.



回答5:

Twitter API results are sorted by recent by default. Please see the following quote from twitter wiki :

Parameter to Twitter search API :

result_type: Optional. Specifies what type of search results you would prefer to receive.

* Valid values include:         o mixed: In a future release this will become the default value. Include both popular and real time results in the response.       o recent: The current default value. Return only the most recent results in the response.       o popular: Return only the most popular results in the response. * Example: http://search.twitter.com/search.atom?q=Twitter&result_type=mixed * Example: http://search.twitter.com/search.json?q=twitterapi&result_type=popular * Example: http://search.twitter.com/search.atom?q=justin+bieber&result_type=recent 

Please correct me if I am wrong anywhere.

Thanks and Regards,
Abhay Dandekar



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