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问题:
I need to read a jpg file to a string. I want to upload this file to our server, I just find out that the API requires a string as the data of this pic. I followed the suggestions in a former question I've asked Upload pics to a server using c++ .
int main() { ifstream fin("cloud.jpg"); ofstream fout("test.jpg");//for testing purpose, to see if the string is a right copy ostringstream ostrm; unsigned char tmp; int count = 0; while ( fin >> tmp ) { ++count;//for testing purpose ostrm << tmp; } string data( ostrm.str() ); cout << count << endl;//ouput 60! Definitely not the right size fout << string;//only 60 bytes return 0; }
Why it stops at 60? It's a strange character at 60, and what should I do to read the jpg to a string?
UPDATE
Almost there, but after using the suggested method, when I rewrite the string to the output file, it distorted. Find out that I should also specify that the ofstream is in binary mode by ofstream::binary
. Done!
By the way what's the difference between ifstream::binary
& ios::binary
, is there any abbreviation for ofstream::binary
?
回答1:
Open the file in binary mode, otherwise it will have funny behavior, and it will handle certain non-text characters in inappropriate ways, at least on Windows.
ifstream fin("cloud.jpg", ios::binary);
Also, instead of a while loop, you can just read the whole file in one shot:
ostrm << fin.rdbuf();
回答2:
You shouldn't read the file to a string because it is legal for a jpg to contain values that are 0. However in a string, the value 0 has a special meaning (it's the end of string indicator aka \0). You should instead read the file into a vector. You can do this easily like so:
#include <algorithm> #include <iostream> #include <fstream> #include <vector> int main(int argc, char* argv[]) { std::ifstream ifs("C:\\Users\\Borgleader\\Documents\\Rapptz.h"); if(!ifs) { return -1; } std::vector<char> data = std::vector<char>(std::istreambuf_iterator<char>(ifs), std::istreambuf_iterator<char>()); //If you really need it in a string you can initialize it the same way as the vector std::string data2 = std::string(std::istreambuf_iterator<char>(ifs), std::istreambuf_iterator<char>()); std::for_each(data.begin(), data.end(), [](char c) { std::cout << c; }); std::cin.get(); return 0; }
回答3:
Try opening the file in binary mode:
ifstream fin("cloud.jpg", std::ios::binary);
At a guess, you were probably trying to read the file on Windows and the 61st character was probably 0x26 -- a control-Z, which (on Windows) will be treated as marking the end of the file.
As far as how to best do the reading, you end up with a choice between simplicity and speed, as demonstrated in a previous answer.