Run shell command from child shell

匿名 (未验证) 提交于 2019-12-03 01:38:01

问题:

I have a Unix shell script test.sh. Within the script i would like to invoke another shell and then execute the rest of the commands in the shell script from the child shell and exit

To make it clear:

test.sh

#! /bin/bash  /bin/bash /* create child shell */  <shell-command1> <shell-command2> ......  <shell-commandN>  exit 0

What my intention is to run the shell-commands1 to shell-commandN from the child shell. Kindly tell me how to do this

回答1:

You can setup in a group, like.

#!/bin/bash ( Command1 Command2 etc.. )  subshell() {     echo "this is also within a subshell" }  subshell

( and ) creates a subshell in which you run a group of commands, otherwise a simple function will do. I don't know if ( and ) is POSIX compatible.

Update: If I understand your comment correctly, you want to be using -c option with bash, like.

/bin/bash -c "Command1 && Command2...." &


回答2:

From http://tldp.org/LDP/abs/html/subshells.html here is an example:

#!/bin/bash # subshell-test.sh  ( # Inside parentheses, and therefore a subshell . . . while [ 1 ]   # Endless loop. do   echo "Subshell running . . ." done )  #  Script will run forever, #+ or at least until terminated by a Ctl-C.  exit $?  # End of script (but will never get here).


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