SQLAlchemy - Self referential Many-to-many relationship with extra column

匿名 (未验证) 提交于 2019-12-03 01:31:01

问题:

I have a model representing user and I want to create a relationship between users representing that they are friends. My functional model with association table and methods to list all the friends look like this

friendship = db.Table('friend',     db.Column('id', db.Integer, primary_key=True),     db.Column('fk_user_from', db.Integer, db.ForeignKey('user.id'), nullable=False),     db.Column('fk_user_to', db.Integer, db.ForeignKey('user.id'), nullable=False) )  class User(db.Model):    ...    ...    friends = db.relationship('User',         secondary=friendship,         primaryjoin=(friendship.c.fk_user_from==id),         secondaryjoin=(friendship.c.fk_user_to==id),         backref = db.backref('friend', lazy = 'dynamic'),          lazy = 'dynamic')      def list_friends(self):         friendship_union = db.select([                         friendship.c.fk_user_from,                          friendship.c.fk_user_to                         ]).union(                             db.select([                                 friendship.c.fk_user_to,                                  friendship.c.fk_user_from]                             )                     ).alias()         User.all_friends = db.relationship('User',                        secondary=friendship_union,                        primaryjoin=User.id==friendship_union.c.fk_user_from,                        secondaryjoin=User.id==friendship_union.c.fk_user_to,                        viewonly=True)          return self.all_friends

The problem is that I need to implement asking for frienship and status pending before confirmation (just like you know it from Facebook) so it is necesarry to add an extra column to the frienship table. According to the SQLAlchemy tutorial I should create an Association Object but how to make it self referential again?

Or is it possible to just add this column to my current frienship table and access and change the status value there somehow?

Thanks

回答1:

All you need is to add primaryjoin in your table and also making two foreignkey in table of Friendship, 'primary_key' too. you also need to make friendship as a class.

class Friendship(db.Model):     __tablename__ = 'friend'     fk_user_from = db.Column(db.Integer, db.ForeignKey('user.id'), primary_key=True)     fk_user_to = db.Column(db.Integer, db.ForeignKey('user.id'), primary_key=True)     extra_field = db.Column(db.Integer)   class User (db.Model):     __tablename__ = 'user'     id = db.Column(db.Integer, primary_key=True)     user_to = db.relationship('Friendship',backref='to', primaryjoin=id==Friendship.fk_user_to)     user_from = db.relationship('Friendship',backref='from', primaryjoin=id==Friendship.fk_user_from )

And to add a friend you need to define Friendship like:

friend = Friendship(extra_field=0 , to=me , from=my_friend)


易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!