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问题:
I'm refactoring a large javascript document that I picked up from an open source project. A number of functions use inconsistent return statements. Here's a simple example of what I mean:
var func = function(param) { if (!param) { return; } // do stuff return true; }
Sometimes the functions return boolean, sometimes strings or other things. Usually they are inconsistently paired with a simple return;
statement inside of a conditional.
The problem is that the code is complex. It is a parser that uses a multitude of unique RegEx matches, creates and destroys DOM nodes on the fly, etc. Preliminary testing shows that, in the above example, I could change the return;
statement to become return false;
, but I'm concerned that I may not realize that it had a negative impact (i.e. some feature stopped working) on the script until much later.
So my questions: Is there a benefit to using a blank return statement? Could this have been intentionally coded this way or was it just lazy? Can I change them all to return false;
, or return null;
or do I need to dig through every call and find out what they are doing with the results of those functions?
回答1:
Using return
without a value will return the value undefined
.
If the value is evaluated as a boolean, undefined
will work as false
, but if the value for example is compared to false
, you will get a different behaviour:
var x; // x is undefined alert(x); // shows "undefined" alert(!x); // shows "true" alert(x==false); // shows "false"
So, while the code should logically return true
or false
, not true
or undefined
, you can't just change return;
to return false;
without checking how the return value is used.
回答2:
"Blank return" statements can be used to transfer the control back to the calling function (or stop executing a function for some reason - ex: validations etc). In most cases I use blank return statement is when I'm doing some kind of a validation. However, I make it a point to set some indicator as to why the execution of the function is stopped. For example, set the "innerText" property on a DIV element with the error message.
In the code above, it looks like it is a validation. The function returns a "true" if everything went well. It looks like the calling function parses the return value, and if it is "true", next step of statements (in the calling function) are executed.
It is a good practice to return "false" instead of a blank return in the above example. That way you make it all uniform and make life easy for other programmers.
You could fix such inconsistencies; however, make sure you test all the changes thoroughly. It is a good practice to test each change you make to the code, however small it may be.
回答3:
What MIGHT be lost here (not direct with your example) is that you can then have a tri-state object:
var myfunc = function(testparam) { if (typeof testparam === 'undefined') return; if (testparam) { return true; } else { return false; } }; var thefirst = myfunc(true) var thesecond = myfunc(false); var thelast = myfunc(); alert("type:" + typeof thefirst+" value:"+thefirst); alert("type:" + typeof thesecond+" value:"+thesecond); alert("type:" + typeof thelast+" value:"+thelast);
these return:
> type:boolean:true > type:boolean:false > type:undefined:undefined
note: null would return false in this example myfunc(null);
回答4:
Changing your functions will actually alter the code because return;
and return false;
output different data types.
var test = function (x) { if (!x) { return; } else { return false; } }; var a = test(true), b = test(false); console.log(typeof b); // boolean console.log(typeof a); // undefined