I need to open link in new tab using Selenium.
So is it possible to perform ctrl+click on element in Selenium to open it in new tab?
I need to open link in new tab using Selenium.
So is it possible to perform ctrl+click on element in Selenium to open it in new tab?
Use an ActionChain
with key_down
to press the control key, and key_up
to release it:
import time from selenium import webdriver from selenium.webdriver.common.action_chains import ActionChains from selenium.webdriver.common.keys import Keys driver = webdriver.Chrome() driver.get('http://google.com') element = driver.find_element_by_link_text('About') ActionChains(driver) \ .key_down(Keys.CONTROL) \ .click(element) \ .key_up(Keys.CONTROL) \ .perform() time.sleep(10) # Pause to allow you to inspect the browser. driver.quit()
Two possible solutions:
opening a new tab
self.driver = webdriver.Firefox() self.driver.find_element_by_tag_name('body').send_keys(Keys.COMMAND + 't')
this is the solution for MAC OSX. In other cases you can use the standard Keys.CONTROL + 't'
opening a new webdriver
driver = webdriver.Firefox() #1st window second_driver = webdriver.Firefox() #2nd windows
Below is what i have tried for Selenium WebDriver with Java binding and its working for me. If you want to manually open the Link in New Tab you can achieve this by performing Context Click on the Link and selecting 'Open in new Tab' option. Below is the implementation in Selenium web-driver with Java binding.
Actions newTab= new Actions(driver); WebElement link = driver.findElement(By.xpath("//xpath of the element")); //Open the link in new window newTab.contextClick(link).sendKeys(Keys.ARROW_DOWN).sendKeys(Keys.ARROW_DOWN).sendKeys(Keys.ENTER).build().perform();
Web-driver handles new tab in the same way to that of new window. You will have to switch to new open tab by its window name.
driver.switchTo().window(windowName);
You can keep track of window-names which will help you to easily navigate between tabs.
Following is working for me to open link in new tab :
String link = Keys.chord(Keys.CONTROL,Keys.ENTER); driver.findElement(By.linkText("yourlinktext")).sendKeys(link);
Above code is in java. you can convert to python easily I assume.
Please ask if have any query.