time

Working with time values greater than 24 hours in R

徘徊边缘 提交于 2020-01-14 14:57:09
问题 I'm trying to perform calculations on time values that are greater than 24 hours. In this short example, I'm trying to calculate someone's sleep duration based on their bedtime and waketime. If bedtime is after midnight, however, the data are entered as time values greater than 24 hours. For example, if someone went to sleep at 2am, their bedtime value is 26:00:00. How can I handle time values greater than 24 hours in R? Here's my short example attempt: library(chron) bedtime <- c("22:37:34",

time complexity trade offs of nfa vs dfa

不想你离开。 提交于 2020-01-14 12:10:44
问题 I am looking for a discussion on which is better used and in what circumstances in a compiler an nfa or dfa. what are the time complexity trade-offs of simulating an nfa vs dfa and which one is more suitable during what circumstances in a compiler?? 回答1: The construction time for a DFA from an NFA is O(2^m) where m is the number of nodes. The running time of a DFA is O(n) where n is the length of the input string. This is because there is only 1 path through the DFA for a given string. The

time complexity trade offs of nfa vs dfa

假如想象 提交于 2020-01-14 12:10:13
问题 I am looking for a discussion on which is better used and in what circumstances in a compiler an nfa or dfa. what are the time complexity trade-offs of simulating an nfa vs dfa and which one is more suitable during what circumstances in a compiler?? 回答1: The construction time for a DFA from an NFA is O(2^m) where m is the number of nodes. The running time of a DFA is O(n) where n is the length of the input string. This is because there is only 1 path through the DFA for a given string. The

time complexity trade offs of nfa vs dfa

拟墨画扇 提交于 2020-01-14 12:09:30
问题 I am looking for a discussion on which is better used and in what circumstances in a compiler an nfa or dfa. what are the time complexity trade-offs of simulating an nfa vs dfa and which one is more suitable during what circumstances in a compiler?? 回答1: The construction time for a DFA from an NFA is O(2^m) where m is the number of nodes. The running time of a DFA is O(n) where n is the length of the input string. This is because there is only 1 path through the DFA for a given string. The

time complexity trade offs of nfa vs dfa

て烟熏妆下的殇ゞ 提交于 2020-01-14 12:09:02
问题 I am looking for a discussion on which is better used and in what circumstances in a compiler an nfa or dfa. what are the time complexity trade-offs of simulating an nfa vs dfa and which one is more suitable during what circumstances in a compiler?? 回答1: The construction time for a DFA from an NFA is O(2^m) where m is the number of nodes. The running time of a DFA is O(n) where n is the length of the input string. This is because there is only 1 path through the DFA for a given string. The

Timing functions

拜拜、爱过 提交于 2020-01-14 09:44:32
问题 Warning, this is a bit recursive ;) I answered this question: Python:How can i get all the elements in a list before the longest element? And after I submitted there where another answer that should be faster (the author thought, and so did I). I tried to time the different solutions but the solution that should be slower was actually faster. This made me think there is something wrong with my code. Or is it? import string import random import time def solution1(lst): return lst[:lst.index

cancel/stop jquery fadeOut after begin

若如初见. 提交于 2020-01-14 07:57:26
问题 I've got a very simple page that shows a status update when a user clicks on specific entries on the page. This is all working fine. The first click updates the id='sts' with the correct output, after 6 seconds this fades away. However whilst it's fading if the user clicks another link the DIV is updated with the new text, but it continues to fade away based on the original fadeout time out. Anyway to have the DIV updates start the fade counter again ? This is what I'm currently using to do

Get time interval in mysql

浪尽此生 提交于 2020-01-14 07:40:07
问题 is there a query for me to get the time interval - One minute, five minutes, quarter hour, half hour, hour, and day? I use MySQL as a database. 回答1: to get a range, like from 30 to 45 minutes ago, do like this SELECT * FROM tbl WHERE tbl.mydate > DATE(DATE_sub(NOW(), INTERVAL 45 MINUTE)) AND tbl.mydate < DATE(DATE_sub(NOW(), INTERVAL 30 MINUTE)); 回答2: You are probably looking for date_sub: SELECT * FROM YOURTABLE t WHERE t.timestamp > date_sub(NOW(), interval 1 hour); For different intervals

NSTime create a timeInterval

倖福魔咒の 提交于 2020-01-14 06:43:42
问题 I have the following code in my application in the method updateLabel2 : timeLeft = [[NSDate date] timeIntervalSinceDate:[[NSUserDefaults standardUserDefaults] objectForKey:@"lastDate"]]; [[self timer] setText:[NSString stringWithFormat:@"Time Remaining: %f", timeLeft]]; //Set the label text Note that timer is a label. and earlier, the following code is executed: [[NSUserDefaults standardUserDefaults] setObject:[NSDate date] forKey:@"lastDate"]; self.repeatTimer = [NSTimer

What is the best way to run a function every 5 minutes in python synced with system clock?

一笑奈何 提交于 2020-01-14 04:32:06
问题 I want to run a function every 5 minutes and have it synced with the clock. If I use time.sleep(60*5), the time starts to drift because my function adds a tiny bit of processing time. Is this a good way of running my function synced with the clock or is there a better way in python? def run(condition): def task(): #run data here pass runOnce = True while condition: if dt.datetime.now().minute % 5 == 0 and dt.datetime.now().second == 0 and runOnce: runOnce = False task() elif dt.datetime.now()