time

问题 I have 2 functions. First one converts time_t to string. Second one string to time_t. I just have the date that needs to be converted and restored back as string. The functions are void split(const string &s, char delim, vector<string>& elems) { stringstream ss(s); string item; while(getline(ss, item, delim)) { elems.push_back(item);} return; } time_t getDateInTimeTfromHyphenSplitString(string s) { struct tm tmvar = {0}; vector<string> tim; split(s.c_str(),'-',tim); tmvar.tm_year = atoi(tim[2

问题 I need to get the date as one string and the current time as another in C. I've had a look at time.h and see it allows me to get the whole thing. Do I then have to use some string methods? I notice that C doesn't have a substring method? Strcpy seems like it might work but I need a char * not an array. Any advice? Thanks 回答1: You can use strftime for this: struct tm *tm; time_t t; char str_time[100]; char str_date[100]; t = time(NULL); tm = localtime(&t); strftime(str_time, sizeof(str_time),

问题 Trying to join 2 dataframes according to multiple conditions and time interval condition like in the following example: # two sample dataframes with time intervals df1 <- data.frame(key1 = c("a", "b", "c", "d", "e"), key2 = c(1:5), time1 = as.POSIXct(hms::as.hms(c("00:00:15", "00:15:15", "00:30:15", "00:40:15", "01:10:15"))), time2 = as.POSIXct(hms::as.hms(c("00:05:15", "00:20:15", "00:35:15", "00:45:15", "01:15:15")))) %>% mutate(t1 = interval(time1, time2)) %>% select(key1, key2, t1) df2 <-

问题 I understand that it's pretty easy to display local time to a user given an offset from GMT for the timezone (e.g. -7 hours for Pacific Daylight Time). But, what if I want to continue to display the correct local time for a long period of time (say 1 year). Given just an offset from GMT, you do not know what timezone the user is in. E.g. given -7, the user may live in the US or in Canada (or in some other country). These countries my have different local times at different points of the year

问题 I've came across a problem to convert a Day of Week string into a time.Weekday value. I couldn't find anything built into the time package. Then I've written this simple function (that covers my needs): var daysOfWeek = [...]string{ "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", } func parseWeekday(v string) (time.Weekday, error) { for i := range daysOfWeek { if daysOfWeek[i] == v { return time.Weekday(i), nil } } return time.Sunday, fmt.Errorf("invalid weekday

问题 I have a dataset organized this way: ID Species DateTime P1 A 2015-03-16 18:42:00 P2 A 2015-03-16 19:34:00 P3 A 2015-03-16 19:58:00 P4 A 2015-03-16 21:02:00 P5 B 2015-03-16 21:18:00 P6 A 2015-03-16 21:19:00 P7 A 2015-03-16 21:33:00 P8 B 2015-03-16 21:35:00 P9 B 2015-03-16 23:43:00 I want to select independent pictures for each species (that is, pictures separated from each other by 1h), in this dataset with R. In this example, for species A, I would only want to keep P1, P3 and P4. P2 wouldn

问题 First, I give thanks to ksav and his help thus far. I'm a foreman for a landscaping company and it's my responsibility to fill out forms for each site and keep track of our man hours so we don't go over the allotted time. I'm trying to digitize the documents in Adobe so I can enter the times in the field on my phone without pen and paper and have a JavaScript code automatically calculate the hours on site in decimal format. Note: I will be using 24-hour time aka military time (13:00/1PM 16:40

问题 I need to stop the sync from a windows server 2008 r2 from sync. Already stop the windows time service, but it sync in 2 seconds. how can i delay 1 day in the clock and dont sync ? 回答1: TO do it, i have to stop this two services Hyper-V Time Synchronization Service Windows Time 回答2: temporarely stopping the service: net stop w32time unregistering the service: W32tm /unregister 回答3: http://kb.vmware.com/selfservice/microsites/search.do?language=en_US&cmd=displayKC&externalId=1318 If running a

问题 Someone does 20 Hours 42 Minutes & 16 Seconds in one shift totaling 74536 seconds. How do I get the hours from number of seconds the person has done for that shift? 20 * 60 * 60 = 72000 42 * 60 = 2520 16 = 16 + ----- Total = 74536 ____________________________ Total % 60 = Seconds (16) Total % ? = Minutes (42) Total % ? = Hours (20) Tried 84600 already; turns out when a number is lower the modulus, it really is not very helpful, and something I am going to have to catch should someone only

问题 I want to be able to implement a condition in my program where it would only run for N number of hours, maybe the user could specify N, but let's not jump ahead. I figured I could use datetime.now() and store the value below in a variable, time >>> time >>> time = datetime.datetime(2013, 12, 9, 21, 50, 32, 405329) Any ideas on how I can access the fourth field between the (--), seeing as it's a string? My condition would be something like while time != timeEnd where timeEnd would be the value