string-interpolation

related to question: How do I substitute with an evaluated expression in Perl? In Perl, is there a way like in Ruby to do: $a = 1; print "#{$a + 1}"; and it can print out 2 ? There's a similar shorthand in Perl for this: $a = 1; print "@{[$a + 1]}" This works because the [] creates a reference to an array containing one element (the result of the calculation), and then the @{} dereferences the array, which inside string interpolation prints each element of the array in sequence. Since there is only one, it just prints the one element. You can use the @{[ EXPRESSION ]} trick that Greg Hewgill

I've been using string interpolation and loving it, however I have an issue where I am trying to include a backslash in my output, but am not able to get it to work. What I want is something like this.. var domain = "mydomain"; var userName = "myUserName"; var combo = $"{domain}\{userName}" I want the output of combo to be myDomain\myUserName What I am getting is a syntax error about the \ being an escape character. If I put in \\ then the snytax error is gone, but the output is myDomain\\myUsername How can I include escaped characters in an interpolated string? birdamongmen Escaping with a

In C#6 there is a new feature: interpolated strings. These let you put expressions directly into code, rather than relying on indexes: string s = string.Format("Adding \"{0}\" and {1} to foobar.", x, this.Y()); Becomes: string s = $"Adding \"{x}\" and {this.Y()} to foobar."; However, we have a lot of strings across multiple lines using verbatim strings (mainly SQL statements) like this: string s = string.Format(@"Result... Adding ""{0}"" and {1} to foobar: {2}", x, this.Y(), x.GetLog()); Reverting these to regular strings seems messy: string s = "Result...\r\n" + $"Adding \"{x}\" and {this.Y()

I can't get string interpolation to work. Last news from MS I found was http://blogs.msdn.com/b/csharpfaq/archive/2014/11/20/new-features-in-c-6.aspx However all that is said there is not working. Anyone knows if string interpolation made it into VS 2015? Is there any documentation about it? Can one you give an example? For instance, none of these formats work ( edited ): int i = 42; var s = "\{i}"; // correction after jon's answer: this works! var s = $"{i}"; // compiler error var s = "{{i}}"; // no interpolation edit about VS 2015 CTP 6 (20.4.2015 ) The final version is var s = $"{i}" also

CodeDomProvider objCodeCompiler = CodeDomProvider.CreateProvider( "CSharp" ); CompilerParameters objCompilerParameters = new CompilerParameters(); ... CompilerResults objCompileResults = objCodeCompiler.CompileAssemblyFromFile( objCompilerParameters, files.ToArray() ); When I compile my files I get: FileFunctions.cs(347): Error: Unexpected character '$' Does anyone know how to get string interpolation working with CodeDom compiling? I found this link: How to target .net 4.5 with CSharpCodeProvider? So I tried: var providerOptions = new Dictionary<string, string>(); providerOptions.Add(

String interpolation is available in Scala starting Scala 2.10 This is the basic example val name = "World" //> name : String = World val message = s"Hello $name" //> message : String = Hello World I was wondering if there is a way to do dynamic interpolation, e.g. the following (doesn't compile, just for illustration purposes) val name = "World" //> name : String = World val template = "Hello $name" //> template : String = Hello $name //just for illustration: val message = s(template) //> doesn't compile (not found: value s) Is there a way to "dynamically" evaluate a String like that? (or is

Is there a noticable performance difference between using string interpolation: myString += $"{x:x2}"; vs String.Format()? myString += String.Format("{0:x2}", x); I am only asking because Resharper is prompting the fix, and I have been fooled before. Jeroen Vannevel Noticable is relative. However: string interpolation is turned into string.Format() at compile-time so they should end up with the same result. There are subtle differences though: as we can tell from this question, string concatenation in the format specifier results in an additional string.Concat() call. string interpolation is