string-interpolation

In Perl I can do something like the following: my $home = "/home"; my $alice = "$home/alice"; Can I do something like the following in YAML: Home: /home Alice: $Home/alice So "Alice" is effectively /home/alice in the end? Paul Fioravanti Unfortunately, you're out of luck. To do what you want you'd need to pass in $home from a view file (or wherever) and interpolate it in your yaml entry, which could possibly look something like: Alice: ! '%{home}/Alice' See this StackOverflow Q&A for the detailed answer to pretty much exactly your question. You should use ERB template. you can write like

This question already has an answer here: How to format strings in Java 6 answers String building in Java confounds me. I abhore doing things like: url += "u1=" + u1 + ";u2=" + u2 + ";u3=" + u3 + ";u4=" + u4 + ";"; url += "x=" + u1 + ";y=" + u2 + ";z=" + u3 + ";da1=" + u4 + ";"; url += "qty=1;cost=" + orderTotal + ";ord=" + orderId + "?"; Or, using StringBuilder, something like this: url.append("u1="); url.append(u1); url.append(";u2="); url.append(u2); url.append(";u3="); url.append(u3); url.append(";u4="); url.append(u4); url.append(";"); url.append("x="); url.append(u1); url.append(";y=");

This is a simple script just to see if the file has been downloaded. On this script the find command always evaluated to zero - even if it didn't find anything. So I commented it out. on the filename="day_CTRwFEES_hoo01M_" I had to add an underscore to the end of the filename. Using an underscore $filename_$yesterday.CSV to separate the two did not work. - I had to take out the underscore, add it to the filename and then combine the variables to make it work like this - $filename$yesterday . How could I get it to work without adding the underscore to the end of the variable $filename ? #!/bin

This question already has an answer here: Should I use curly brackets or concatenate variables within strings? 3 answers What is the difference between the two following methods (performance, readability, etc.) and what do you prefer? echo "Welcome {$name}s!" vs. echo "Welcome ".$name."!"; Whatever works best for you works... But if you want to go for speed use this: echo 'Welcome ', $name, '!'; The single quotes tell PHP that no interpretation is needed, and the comma tells PHP to just echo the string, no concatenation needed. 来源： https://stackoverflow.com/questions/16790501/php-variable

Are variables within YAML files possible? For example: theme: name: default css_path: compiled/themes/$theme.name layout_path: themes/$theme.name In this example, how can theme: name: default be used in other settings? What is the syntax? benrugg I had this same question, and after a lot of research, it looks like it's not possible . The answer from cgat is on the right track, but you can't actually concatenate references like that. Here are things you can do with "variables" in YAML (which are officially called "node anchors" when you set them and "references" when you use them later): Define