string-interpolation

Escape a dollar sign in string interpolation

半腔热情 提交于 2019-11-28 18:30:16
How do I escape a dollar sign in string interpolation? def getCompanion(name: String) = Class.forName(s"my.package.$name\$") // --> "error: unclosed string literal" Just double it scala> val name = "foo" name: String = foo scala> s"my.package.$name$$" res0: String = my.package.foo$ 来源: https://stackoverflow.com/questions/16875530/escape-a-dollar-sign-in-string-interpolation

Does Python do variable interpolation similar to “string #{var}” in Ruby?

試著忘記壹切 提交于 2019-11-28 18:13:05
In Python, it is tedious to write: print "foo is" + bar + '.' Can I do something like this in Python? print "foo is #{bar}." Sean Vieira Python 3.6+ does have variable interpolation - prepend an f to your string: f"foo is {bar}" For versions of Python below this (Python 2 - 3.5) you can use str.format to pass in variables: # Rather than this: print("foo is #{bar}") # You would do this: print("foo is {}".format(bar)) # Or this: print("foo is {bar}".format(bar=bar)) # Or this: print("foo is %s" % (bar, )) # Or even this: print("foo is %(bar)s" % {"bar": bar}) Python 3.6 will have has literal

How to solve “String interpolation produces a debug description for an optional value; did you mean to make this explicit?” in Xcode 8.3 beta?

家住魔仙堡 提交于 2019-11-28 16:56:25
Since beta 8.3, zillions warnings "String interpolation produces a debug description for an optional value; did you mean to make this explicit?" appeared in my code. For example, the warning popped in the following situation up, where options could lead to nil: let msg = "*** Error \(options["taskDescription"]): cannot load \(sUrl) \(error)" As previously designed, it was ok for me (and the compiler) the optionals to be interpolated as 'nil'. But compiler changed its mind. What the compiler suggests is to add a String constructor with description as follows: let msg = "*** Error \(String

Patternlab / Twig Variable Interpolation doesn't work with string from json

*爱你&永不变心* 提交于 2019-11-28 13:11:55
I'm working on a project that's based on the twig patternlab framework. I'm using JSON files for most of my content, especially for pages. I want to integrate a link (build by an atom) into a text I got from my JSON file that has a placeholder for the link. I'm working with texts from a multilingual cms so putting a placeholder into the text content is the easiest way to keep it flexible. This is an excerpt from my json file { "legal" : "Mit dem Absenden des Formulars akzeptieren Sie unsere #{ legalLink }.", "deeplink" : { "label" : "Datenschutzbedingungen", "url" : "#AGB_link" } } and this is

Generate All Possible Matches of a Regular Expression [closed]

北慕城南 提交于 2019-11-28 13:06:45
问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 4 years ago . How can I derive all possible matches of a regular expression For example: ((a,b,c)o(m,v)p,b) The strings generated from above expression would be: aomp bomp comp aovp bovp covp b 回答1: Your steps are pretty straight forward though implementing them may take a bit of work: Create a

Using a Variable (PowerShell) inside of a command

六眼飞鱼酱① 提交于 2019-11-28 12:28:39
$computer = gc env:computername # Argument /RU '$computer'\admin isn't working. SchTasks /create /SC Daily /tn "Image Verification" /ST 18:00:00 /TR C:\bdr\ImageVerification\ImageVerification.exe /RU '$computer'\admin /RP password Basically I need to provide the computer name in the scheduled task... Thank you in advance! Single quoted strings will not expand variables in PowerShell. Try a double quoted string e.g.: "$computer\admin" use the command 'hostname' to get the name of the local pc. 来源: https://stackoverflow.com/questions/12393999/using-a-variable-powershell-inside-of-a-command

String interpolation doesn't work with .NET Framework 4.6

ぃ、小莉子 提交于 2019-11-28 11:53:15
I just installed the .NET Framework 4.6 on my machine and then created a ConsoleApplication targeting .NET Framework 4.6 with Visual Studio 2013. I wrote the following in the Main method: string test = "Hello"; string format = $"{test} world!"; But this does not compile. Doing the same in Visual Studio 2015 works. Why? String interpolation is a C# 6.0 feature, not one of .NET Framework 4.6. VS 2013 doesn't support C# 6 but VS 2015 does. String interpolation is indeed a C# 6.0 feature, but C# 6 isn't limited to VS2015. You can compile applications that leverage C# 6.0 language features in

Python string interpolation implementation

牧云@^-^@ 提交于 2019-11-28 11:23:46
[EDIT 00]: I've edited several times the post and now even the title, please read below. I just learned about the format string method, and its use with dictionaries, like the ones provided by vars() , locals() and globals() , example: name = 'Ismael' print 'My name is {name}.'.format(**vars()) But I want to do: name = 'Ismael' print 'My name is {name}.' # Similar to ruby So I came up with this: def mprint(string='', dictionary=globals()): print string.format(**dictionary) You can interact with the code here: http://labs.codecademy.com/BA0B/3#:workspace Finally, what I would love to do is to

Can I postpone/defer the evaluation of f-strings?

南笙酒味 提交于 2019-11-28 08:51:58
I am using template strings to generate some files and I love the conciseness of the new f-strings for this purpose, for reducing my previous template code from something like this: template_a = "The current name is {name}" names = ["foo", "bar"] for name in names: print (template_a.format(**locals())) Now I can do this, directly replacing variables: names = ["foo", "bar"] for name in names: print (f"The current name is {name}") However, sometimes it makes sense to have the template defined elsewhere -- higher up in the code, or imported from a file or something. This means the template is a

How to manually interpolate a string? [duplicate]

独自空忆成欢 提交于 2019-11-28 07:36:45
问题 This question already has an answer here: How replace variable in string with value in php? 11 answers The only way I've found to interpolate a string (I.E. expand the variables inside it) is the following: $str = 'This is a $a'; $a = 'test'; echo eval('return "' . $str . '";'); Keep in mind that in a real-life scenario, the strings are created in different places, so I can't just replace ' s with " s. Is there a better way for expanding a single-quoted string without the use of eval()? I'm