sort

Sorting list of list of elements of a custom class in R?

匿名 (未验证) 提交于 2019-12-03 02:31:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I have a custom class object (list of tuples). I have defined <.myclass >.myclass and ==.myclass on it as well. Now I have a a <- obj1 # of myclass b <- obj2 # of myclass c <- obj3 # of myclass L <- list ( list ( a , 12 , 1 ), list ( b , 215 , 23 ), list ( c , 21 , 9 )) I want to sort L, on index 1. i.e. I have b < c < a then, I want sorted L in this form list(list(b,215,23),list(c,21,9),list(a,12,1)) How do I achieve this? In my searches, I found how to sort on particular index, and using that I wrote the following function magic

Sort documents in collections while fetching

匿名 (未验证) 提交于 2019-12-03 02:31:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I have a collection called at MongoDB called resource. It has the following documents: { "_id" : "Abb.e" , "_class" : "Resource" , "resourceEmail" : "test1@test.com" } { "_id" : "Dasd.tt" , "_class" : "Resource" , "resourceEmail" : "test2@test.com" } { "_id" : "Bbb.rr" , "_class" : "Resource" , "resourceEmail" : "test3@test.com" } At Java code,I list them as follows: MongoOperations mongoOperations = mongoConfiguration . getMongoTemplate (); List < Resource > resourceList = mongoOperations . findAll ( Resource . class ); return

How to sort huge files with Python?

匿名 (未验证) 提交于 2019-12-03 02:31:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I found some this promising code on activestate.com to sort huge files. I'm trying to run it on the default Python 2.6.5 interpreter on Ubuntu 10.04. When I try running it on a small test file, I get the error trace below. I asked for help on activestate.com, but this thread has been silent for over 18 months. Is there anyone here who sees an obvious solution? Thanks. ## {{{ http://code.activestate.com/recipes/576755/ (r3) # based on Recipe 466302: Sorting big files the Python 2.4 way # by Nicolas Lehuen import os from tempfile

How to sort a std::set with const getters

匿名 (未验证) 提交于 2019-12-03 02:30:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have a std::set container whose elements are objects of the following class: class LaneConnector { public: const Lane* getLaneFrom() const { return From; } const Lane* getLaneTo() const { return To; } private: Lane* From; Lane* To; } and my comparator function is as follows: struct MyLaneConectorSorter { bool operator() (LaneConnector * c, LaneConnector * d) { Lane* a = const_cast<Lane*>(c->getLaneFrom()); Lane* b = const_cast<Lane*>(d->getLaneFrom()); return (a->getLaneID() < b->getLaneID()); } } myLaneConnectorSorter; Now when I try to

First common element from two lists

匿名 (未验证) 提交于 2019-12-03 02:30:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: x = [8,2,3,4,5] y = [6,3,7,2,1] How to find out the first common element in two lists (in this case, "2") in a concise and elegant way? Any list can be empty or there can be no common elements - in this case None is fine. I need this to show python to someone who is new to it, so the simpler the better. UPD: the order is not important for my purposes, but let's assume I'm looking for the first element in x that also occurs in y. 回答1: This should be straight forward and almost as effective as it gets (for more effective solution check Ashwini

Sort months ( with strings ) algorithm

匿名 (未验证) 提交于 2019-12-03 02:30:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have this months array: ["January", "March", "December" , "October" ] And I want to have it sorted like this: ["January", "March", "October", "December" ] I'm currently thinking in a "if/else" horrible cascade but I wonder if there is some other way to do this. The bad part is that I need to do this only with "string" ( that is, without using Date object or anything like that ) What would be a good approach? 回答1: If I had a way to supply a custom sorting order, I'd create a list defining the correct order: correct = List("January",

Java how to sort lowercase before uppercase strings

匿名 (未验证) 提交于 2019-12-03 02:30:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I want the files to be ordered by their abs path name, but I want the lowercase to be sorted before the uppercase. Example: Let's say I got 4 files: files2.add("b"); files2.add("A"); files2.add("a"); files2.add("B"); the order with this code is: [A, B, a, b] I want it to be: [a, A, b, B] import java.io.File; import java.util.*; public class Abs { public ArrayList<File> getOrder(ArrayList<File> files) { Collections.sort(files, new Comparator<File>() { public int compare(File file1, File file2) { return file1.getAbsolutePath().compareTo(file2

How to sort an ArrayList with object using stream().sorted()

匿名 (未验证) 提交于 2019-12-03 02:29:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am having real trouble with using stream and sorted to sort my ArrayList and hope someone can help out. The code uses Croatian words, but I don't think that will be a problem for someone who understands what I mean. This is the ArrayList ArrayList<Publikacija> listaPublikacija = new ArrayList<>(); listaPublikacija.add(prvaKnjiga); listaPublikacija.add(drugaKnjiga); listaPublikacija.add(prviCasopis); listaPublikacija.add(drugiCasopis); In my assignment I am supposed to sort these objects above by getCijena() which is double. This is the

how to sort varchar column containing numeric values with linq lambdas to Entity

匿名 (未验证) 提交于 2019-12-03 02:27:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am using linq lambdas to query the MySql (Note MySql not Sql) with Entity Framwork in MVC. Now i have one table product one of column this table is price with datatype "VARCHAR" (Accept i can't change type to INT as it can hold values like "N/A",etc). I want to sort price column numerically with linq Lambdas.I have tried bellow.I am using Model values to filter query. var query = ent.Product.Where(b => b.cp == Model.CodePostal); if (Model.order_by_flg == 2) { query = query.OrderByDescending(a => a.price.PadLeft(10, '0')); } But it will not

How to sort git tags by version string order of form rc-X.Y.Z.W?

匿名 (未验证) 提交于 2019-12-03 02:27:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: When I enter a command: git tag -l I get such results: rc-0.9.0.0 rc-0.9.0.1 rc-0.9.0.10 rc-0.9.0.11 rc-0.9.0.12 rc-0.9.0.2 rc-0.9.0.3 rc-0.9.0.4 rc-0.9.0.5 rc-0.9.0.6 rc-0.9.0.7 rc-0.9.0.8 rc-0.9.0.9 Instead of this I want: rc-0.9.0.0 rc-0.9.0.1 rc-0.9.0.2 rc-0.9.0.3 rc-0.9.0.4 rc-0.9.0.5 rc-0.9.0.6 rc-0.9.0.7 rc-0.9.0.8 rc-0.9.0.9 rc-0.9.0.10 rc-0.9.0.11 rc-0.9.0.12 How it's possible to sort current list to get such results? 回答1: Use version sort git tag -l | sort -V or for git version >= 2.0 git tag -l --sort=v:refname git tag -l --sort=