问题:

I have a collection called at MongoDB called resource. It has the following documents:

{ "_id" : "Abb.e", "_class" : "Resource", "resourceEmail" : "test1@test.com" } { "_id" : "Dasd.tt", "_class" : "Resource","resourceEmail" : "test2@test.com" } { "_id" : "Bbb.rr", "_class" : "Resource", "resourceEmail" : "test3@test.com" }

At Java code,I list them as follows:

 MongoOperations mongoOperations = mongoConfiguration.getMongoTemplate();   List<Resource> resourceList = mongoOperations.findAll(Resource.class);   return resourceList;

How could I fetch these documents sorted by ID !

回答1:

As you're using Spring Data, you could use a Query object to query all documents in the colletion and sort the results.

MongoOperations mongoOperations = mongoConfiguration.getMongoTemplate(); Query q = new Query().with(new Sort(Sort.Direction.ASC, "_id")); List<Resource> resourceList = mongoOperations.find(q, Resource.class); return resourceList;

Of course that you could iterate the list of results and sort it manually, or even use Collection.sort method, but I think if you have an index in the property that you're using to sort, it's faster to mongodb sort the results.

回答2:

Should be something like this:

 MongoOperations mongoOperations = mongoConfiguration.getMongoTemplate();   List<Resource> resourceList = mongoOperations.findAll(Resource.class).sort({'_id' : 1});   return resourceList;

You need to append .sort({'_id' : 1}) for ascending order or .sort({'_id' : -1}) for descending order.

For Java:

.sort( new BasicDBObject( "_id" , 1 ) )

Solution from echo:

DBCursor dbCursor = mongoOperations.getCollection(RESOURCE_COLLECTION_NAME).find().sort(new BasicDBObject("_id", 1));  List<DBObject> dbObjects = dbCursor.toArray();  List<Map> items = new ArrayList<Map>(dbCursor.length());  for (DBObject dbObject : dbObjects) {   Map map = dbObject.toMap();   items.add(dbObject.toMap());  }

转载请标明出处:Sort documents in collections while fetching

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