range

>>> k = 8 >>> for i in range(k): print i k -= 3 print k Above the is the code which prints numbers from 0-7 if I use just print i in the for loop. I want to understand the above code how it is working, and is there any way we can update the value of variable used in range(variable) so it iterates differently. Also why it always iterates up to the initial k value, why the value doesn't updated. I know it's a silly question, but all ideas and comments are welcome. You can't change the range after it's been generated. In Python 2, range(k) will make a list of integers from 0 to k, like this: [0,

Here is some HTML that I am working with in my UIWebView: <div id = "1"> <span style = "background-color:red"> <a href = "10&20"> This is a link </a> </span> </div> Once the link is tapped, I want to programmatically select the link text in the UIWebView (so "This is a link" would now be highlighted with the blue iOS text selection tool). This is why I am sending some range information in the href of the a tag. This is the call I am using to try and make this programmatic selection: //set content editable true [self.webView stringByEvaluatingJavaScriptFromString:[NSString stringWithFormat:@

I'm just trying to do a simple cut and paste to shift ranges in F:G to an unoccupied cell in D but I keep getting that error message. My codes are in the Modules and I don't know what I'm doing wrong! Completely new to VBA. Highlighted portion: Range("F" & RowNum & ":G" & RowNum).Select Sub MoveCells(RowNum as Integer) Range(“F” & RowNum & ":G" & RowNum).Select Selection.Cut Range(“D” & RowNum).Select ActiveSheet.Paste End Sub Range(“F” & RowNum & ":G" & RowNum).Select ^ ^ ^ ^ | | | | Chr(147) Chr(34) The 'quotation marks' around F are character 147. To denote a string value you have to use

I need to define a function called rec_range(n) which takes a natural number and returns a TUPLE of numbers up to the number n. i.e. rec_range(5) returns (0,1,2,3,4) rec_range(1) returns (0,) This is what I have come up with so far. def rec_range(n): """takes a natural number n and returns a tuple of numbers starting with 0 and ending before n Natural Number -> Tuple of Numbers""" if n == 0: return 0 else: return (rec_range(n-1), ) This works for rec_range(1). ***Restrictions are: must be defined recursively, cannot use lists, loops or use the existing range() function I would write it as

I want to merge cells in columns, if there is the same value in whole row. Eg. If A1:G1 range is the same as A2:G2 I want to merge A1:A2 cells, B1:B2 to G1:G2. With my code below I get run time error 13: type mismatch. I'm assuming, that problem is with checking equality of two ranges. Dim i As Long, j As Long, row as Long row = Cells(Rows.Count, 6).End(xlUp).row For i = row To 7 Step -1 If Range(Cells(i, 7), Cells(i, 24)).Value = Range(Cells(i - 1, 7), Cells(i - 1, 24)).Value Then For j = 7 To 24 Step 1 Range(Cells(i, j), Cells(i - 1, j)).Merge Next j End If Next i The question is, how to

I'm new with VBA and I'm stuck somewhere. I have to copy last row of column A till column H and paste it untill the last row of column I. Last rows of columnns will be always change. e.g; my data is in A2:H2 and I5 is the last cell with data. My code should be copy A2:H2 and paste it A3:H5. And second time I run the macro (after I add new data to respective columns) it should be copy A6:H6 and paste it untill the last row of column I. I wrote two codes which were not fulfill my needs. first code is ; Sub OrderList1() Range("a65536").End(xlUp).Resize(1, 8).Copy _ (Cells(Cells(Rows.Count, 9).End

I have binary search tree code that inserts numbers randomly. I can modify size each time, but I want to modify the range of numbers, for example: I want the random number be just one digit or just 2 digits. How can I do that? public static void main( String[ ] args ) { BinarySearchTree bst = new BinarySearchTree( ); Random random = new Random( System.currentTimeMillis() ); int[] randoms = new int[1000]; Random randGen = new Random(); for(int i = 0; i < randoms.length; i++) { bst.insert( random.nextInt( randoms.length ) ); } System.out.println( "\n sorted :" ); bst.inorderTraversal( ); bst