range

Python Recursion: Range

╄→гoц情女王★ 提交于 2019-12-02 20:02:49
问题 I need to define a function called rec_range(n) which takes a natural number and returns a TUPLE of numbers up to the number n. i.e. rec_range(5) returns (0,1,2,3,4) rec_range(1) returns (0,) This is what I have come up with so far. def rec_range(n): """takes a natural number n and returns a tuple of numbers starting with 0 and ending before n Natural Number -> Tuple of Numbers""" if n == 0: return 0 else: return (rec_range(n-1), ) This works for rec_range(1). ***Restrictions are: must be

setStart and setEnd throwing error when trying to programmatically select text in UIWebView

杀马特。学长 韩版系。学妹 提交于 2019-12-02 19:57:20
问题 Here is some HTML that I am working with in my UIWebView: <div id = "1"> <span style = "background-color:red"> <a href = "10&20"> This is a link </a> </span> </div> Once the link is tapped, I want to programmatically select the link text in the UIWebView (so "This is a link" would now be highlighted with the blue iOS text selection tool). This is why I am sending some range information in the href of the a tag. This is the call I am using to try and make this programmatic selection: //set

JavaScript selection/range framework

僤鯓⒐⒋嵵緔 提交于 2019-12-02 18:27:46
I've been working with selection/range objects, and because to the incredible amount of inconsistencies between browsers for specific selection/range stuff (even more than the DOM) I was wondering if there was a framework that would help me get through them. (Made an answer by request ;) Take a look at IERange : IERange is a feature-complete implementation of W3C DOM Ranges for Internet Explorer, allowing users to write one cross-browser version of their range manipulation code. Supports Range APIs: document.createRange() startContainer , startOffset , endContainer , endOffset ,

filtering lines in a numpy array according to values in a range

不羁的心 提交于 2019-12-02 18:22:32
Let an array: a =np.array([[1,2],[3,-5],[6,-15],[10,7]]) to get lines with elements of the second column above -6 it' s possible to do >>> a[a[:,1]>-6] array([[ 1, 2], [ 3, -5], [10, 7]]) but how to get lines with the second element between -6;3? I tried: >>> a[3>a[:,1]>-6] and also (which raises an error): >>> np.ma.masked_inside(a,-6,3) which gives: masked_array(data = [[-- --] [-- --] [6 -15] [10 7]], mask = [[ True True] [ True True] [False False] [False False]], fill_value = 999999) but the result is not too clear Thanks jp >>> a[ (3>a[:,1]) & (a[:,1]>-6) ] array([[ 1, 2], [ 3, -5]]) The

How can I specify the range of a random number?

空扰寡人 提交于 2019-12-02 17:19:52
问题 I have binary search tree code that inserts numbers randomly. I can modify size each time, but I want to modify the range of numbers, for example: I want the random number be just one digit or just 2 digits. How can I do that? public static void main( String[ ] args ) { BinarySearchTree bst = new BinarySearchTree( ); Random random = new Random( System.currentTimeMillis() ); int[] randoms = new int[1000]; Random randGen = new Random(); for(int i = 0; i < randoms.length; i++) { bst.insert(

VBA copy & paste with dynamic range

感情迁移 提交于 2019-12-02 17:17:49
问题 I'm new with VBA and I'm stuck somewhere. I have to copy last row of column A till column H and paste it untill the last row of column I. Last rows of columnns will be always change. e.g; my data is in A2:H2 and I5 is the last cell with data. My code should be copy A2:H2 and paste it A3:H5. And second time I run the macro (after I add new data to respective columns) it should be copy A6:H6 and paste it untill the last row of column I. I wrote two codes which were not fulfill my needs. first

How to check if two ranges value is equal

痴心易碎 提交于 2019-12-02 15:32:34
问题 I want to merge cells in columns, if there is the same value in whole row. Eg. If A1:G1 range is the same as A2:G2 I want to merge A1:A2 cells, B1:B2 to G1:G2. With my code below I get run time error 13: type mismatch. I'm assuming, that problem is with checking equality of two ranges. Dim i As Long, j As Long, row as Long row = Cells(Rows.Count, 6).End(xlUp).row For i = row To 7 Step -1 If Range(Cells(i, 7), Cells(i, 24)).Value = Range(Cells(i - 1, 7), Cells(i - 1, 24)).Value Then For j = 7

Sum of all integers between two integers [closed]

蓝咒 提交于 2019-12-02 13:45:08
I am using Python and I want to find the sum of the integers between 2 numbers: number1 = 2 number2 = 6 ans = (?) print ans #the numbers in between are 3,4,5 Please give me either the mathematical formula or the Python code to do this. Hint: Given two numbers A and B (both inclusive) where B > A, the sum of values between A & B is given by B(B + 1)/2 - (A - 1)A/2 =(B^2 + B - A^2 + A)/2 =((B - A)(B + A) + (B + A))/2 =(B + A)(B - A + 1)/2 If A & B are both exclusive, then replace B with B - 1 and A with A + 1. The rest I leave it for you as an exercise Read through the Python Expression to

how to array key start from 1 instead of 0?

我的未来我决定 提交于 2019-12-02 13:18:43
How do I start the array of a range at 1 instead of 0, Code looks like this: $numbers = range(0, 14); I tried this but that does not solve my problem $numbers = range(0, 14); You can also go for : $numbers = range(0, 14); array_unshift($numbers,""); unset($numbers[0]); You could try this: $numbers = array_combine(range(1,14), range(1,14)); Try this code These will help you $data = array_slice(range(0,12), 1, null, true); 来源: https://stackoverflow.com/questions/33434201/how-to-array-key-start-from-1-instead-of-0

Set format as plain text

只愿长相守 提交于 2019-12-02 13:15:30
function A1format() { var ss = SpreadsheetApp.getActiveSpreadsheet(); var mainsheet = ss.getSheetByName("Sheet1"); var G = mainsheet.getRange("C15:BH3000").getGridId(); var illa = mainsheet.getRange("A13"); Logger.log(G); illa.copyFormatToRange(G, 16, 3,200, 30); } This doesnt Work and gives some strange Server error. Please help ldo Green answer above is right : in your code the end row is smaller than the start row...(columns are wrong too but it strangely accept this small negative difference) this is indeed not valid. Using the autocomplete feature in the editor will remind you the