range

If I have two ranges that overlap: x = 1..10 y = 5..15 When I say: puts x.include? y the output is: false because the two ranges only overlap partially. But if I want it to be "true" when there is partial overlap between two ranges, how would I write that? In other words I need a way to know when one range contains a subset of another range. I assume there's an elegant way to write this in Ruby but the only solutions I can think of are verbose. Be careful using this with large ranges but this is an elegant way to do it: (x.to_a & y.to_a).empty? The efficient way is to compare the limits (x

I am designing a web application for iPad which makes use of HTML5 in mobile safari. I am transmitting the file manually through an ASP.NET .ashx file hosted on IIS 7 running .NET Framework v2.0. The essential code looks partly like this: // If we receive range header only transmit partial file if (context.Request.Headers["Range"] != null) { var fi = new FileInfo(filePath); long fileSize = fi.Length; // Read start/end index string headerRange = context.Request.Headers["Range"].Replace("bytes=", ""); string[] range = headerRange.Split('-'); int startIndex = Convert.ToInt32(range[0]); int

Hey having a little trouble jquery and the hmtl5 range. I'm try to get the values as they changed but the event listener is not capturing it. Currently my code is: HTML html += '<li>Apply Credits: <input type="range" min="0" max="'+credits+'" name="discount_credits" id="discount_credits" /> <span>'+credits+'</span></li>' And the JS is: $('#discount_credits').mousewheel( function() { alert('it changed!'); alert('new value = ' + $(this).val()); }); I've also tried $('#discount_credits').change( function() { alert('it changed!'); alert('new value = ' + $(this).val()); }); Neither seem to work. Am

Does anyone know if Python has an in-built function to work to print out even values. Like range() for example. Thanks SLaks Range has three parameters. You can write range(0, 10, 2) . Just use a step of 2: range(start, end, step) Try: range( 0, 10, 2 ) I don't know if this is what you want to hear, but it's pretty trivial to filter out odd values with list comprehension. evens = [x for x in range(100) if x%2 == 0] or evens = [x for x in range(100) if x&1 == 0] You could also use the optional step size parameter for range to count up by 2. >>> if 100 % 2 == 0 : print "even" ... even There are

I would like to randomly iterate through a range. Each value will be visited only once and all values will eventually be visited. For example: class Array def shuffle ret = dup j = length i = 0 while j > 1 r = i + rand(j) ret[i], ret[r] = ret[r], ret[i] i += 1 j -= 1 end ret end end (0..9).to_a.shuffle.each{|x| f(x)} where f(x) is some function that operates on each value. A Fisher-Yates shuffle is used to efficiently provide random ordering. My problem is that shuffle needs to operate on an array, which is not cool because I am working with astronomically large numbers. Ruby will quickly

I'm looking for a fluent way of determining if a number falls within a specified set of ranges. My current code looks something like this: int x = 500; // Could be any number if ( ( x > 4199 && x < 6800 ) || ( x > 6999 && x < 8200 ) || ( x > 9999 && x < 10100 ) || ( x > 10999 && x < 11100 ) || ( x > 11999 && x < 12100 ) ) { // More awesome code } Is there a better way of doing this? Anton Gogolev Extension methods? bool Between(this int value, int left, int right) { return value > left && value < right; } if(x.Between(4199, 6800) || x.Between(6999, 8200) || ...) You can also do this awful hack