range

String index out of range: n

由 拜拜、爱过 提交于 2019-12-02 07:47:09
Im having a bit of a problem with this code each time i execute it it gives me an error String index out of range: 'n' n - is the no. of characters that is entered in the textbox pertaining to this code... (that is textbox - t2.)it is stuck at that first textbox checking it does not go over to the next as mentioned in the array. Object c1[] = { t2.getText(), t3.getText(), t4.getText() }; String b; String f; int counter = 0; int d; for(int i =0;i<=2;i++) { b = c1[i].toString(); for(int j=0;j<=b.length();j++) { d = (int)b.charAt(j); if((d<65 || d>90)||(d<97 || d>122)) { counter++; } } } it is

ifort and out of bound Index - Odd Behaviour

由 房东的猫 提交于 2019-12-02 07:45:49
Recently I've resumed Fortran and probably there's something I'm missing but this behaviour looks very odd When I run the following code (compiled with ifort), that just declares an array and sets one of his elements PROGRAM sol_kernel2 IMPLICIT NONE INTEGER, PARAMETER :: jpi=5,jpj=5 REAL, DIMENSION(jpi,jpj) :: sshn PRINT *,jpi,jpj sshn(10,10) = 150.0 PRINT *,sshn(10,10) END PROGRAM sol_kernel2 I expect to get an ERROR Statement, such as SEGMENTATION FAULT, since I'm trying to set the sshn variable using indexes supposed out of memory. I get an error free output like this instead 5 5 150.0000

Generating a random character out of any two in Java

由 故事扮演 提交于 2019-12-02 07:27:22
问题 How do I generate a random character between two specific characters? For e.g; I want to generate either one of 'h' or 'v'. Thanks 回答1: If you want to generate a character, as you say, either h or v, you can generate a random number using the Random class as shown here. If for instance the random number is greater than 0.5, then choose v, if otherwise, choose h. On the other hand, if you have a range of letters, you can either generate an array with the characters you want and generate a

Build an array with a range of MAC addresses [closed]

由 给你一囗甜甜゛ 提交于 2019-12-02 07:18:57
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 years ago . I want to build an array which contains a full list of MAC addresses based on 3 variables: a prefix, a start, and an end. Let's say I have 20:1E:50:3F:8A as a prefix, 3E as a start, and 43 as an end. This should generate the following array of MAC addresses: 20:1E:50:3F:8A:3E 20:1E:50:3F:8A:3F 20:1E:50:3F:8A:40

Sorting range in ascending numerical order containing strings by vba excel

由 做~自己de王妃 提交于 2019-12-02 06:55:41
i have a range containing the following strings: step_1, step_10, step_3, step_2 using the following code input_sh.Activate With ActiveSheet .Range("H2:H20").Select .Sort.SortFields.Clear .Sort.SortFields.Add Key:=Range("H2"), _ SortOn:=xlSortOnValues, Order:=xlAscending, DataOption:=xlSortTextAsNumbers 'xlSortNormal With .Sort .SetRange Range("H2:H20") .Header = xlNo .MatchCase = False .Orientation = xlTopToBottom .SortMethod = xlPinYin .Apply End With step_10, step_1, step_2, step_3 but i would like to get step_1, step_2,step_3,step_10 I would separate the number into another column, your

Generating a random character out of any two in Java

由 ぐ巨炮叔叔 提交于 2019-12-02 06:33:48
How do I generate a random character between two specific characters? For e.g; I want to generate either one of 'h' or 'v'. Thanks If you want to generate a character, as you say, either h or v, you can generate a random number using the Random class as shown here . If for instance the random number is greater than 0.5, then choose v, if otherwise, choose h. On the other hand, if you have a range of letters, you can either generate an array with the characters you want and generate a random number which will be used as an index to choose the random letter, or else, you can generate random

How do I select by a range of starting characters?

由 北城以北 提交于 2019-12-02 06:30:14
问题 Here is my mySQL query: SELECT * FROM `eodList` WHERE datechanged>='$curdate' GROUP BY symbolName ORDER BY dateChanged DESC How do I get all rows (for example) where symbolName starts with letters A-F ? Update: I need something that can be easily changed to another range without alot of code changes. 回答1: Try with Regex WHERE symbolName REGEXP '^[A-F]' 回答2: Faster than Regular expressions and SUBSTRING() function calls. This will use the index of symbolName : WHERE symbolName >= 'A' AND

javascript contentEditable - wrap cross-tag selections

由 杀马特。学长 韩版系。学妹 提交于 2019-12-02 06:16:26
I'm experimenting a bit with contentEditable and encountered this issue: I have the following js snippet var range = document.getSelection().getRangeAt(0); var newNode = document.createElement("span"); newNode.className = "customStyle"; range.surroundContents(newNode); and this HTML fragment: <ul> <li>the <b>only entry</b> of the list</li> </ul> <p>Some text here in paragraph</p> The js code allows to wrap the current selection with a <span> tag. It works perfectly when the selection includes whole HTML tags (e.g. selecting 'the only entry of') but not, of course, when the selection includes

VBA Range variable gone after cut

由 ℡╲_俬逩灬. 提交于 2019-12-02 05:16:58
问题 424 error. Would anyone be kind enough to tell me why the range variable was gone after cut? with sheets(1) Dim des as range set des = .range("A15") .range("A1:A3").cut des msgbox(des.row+5) end with 回答1: A Range object stores a reference to particular cells, not to particular address. When the referenced cells move around, the Range object will follow. E.g. if you store a Range("B1") and then insert a column between A and B, your variable will now have Range("C1") , because your B1 has moved

create a circular list by using a range of angles python

由 偶尔善良 提交于 2019-12-02 04:46:36
问题 I have a list of lists which contains the lower and upper limit of sets of angles something like [[1,22],[2,24]...[359,15],[360,21]] 360 elements in total Now I want to check for each angle from 1 to 360 the elements in the list that contains that angle I was thinking about using the lower and upper limits to create all the elements of the list with range or np.arange(lower,upper) and check if the angle is contained, but np.arange generates empty list when lower is higher than upper for i in
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