python-dateutil

I have a string that has several date values in it, and I want to parse them all out. The string is natural language, so the best thing I've found so far is dateutil . Unfortunately, if a string has multiple date values in it, dateutil throws an error: >>> s = "I like peas on 2011-04-23, and I also like them on easter and my birthday, the 29th of July, 1928" >>> parse(s, fuzzy=True) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/lib/pymodules/python2.7/dateutil/parser.py", line 697, in parse return DEFAULTPARSER.parse(timestr, **kwargs) File "/usr/lib

I am using python-dateutil for parsing a date from a string: import dateutil.parser print dateutil.parser.parse('some null string', fuzzy=True).date() 2012-10-18 print dateutil.parser.parse('some 31 Oct 2012 string', fuzzy=True).date() 2012-10-31 What I am expecting is for dateutil.parser.parse('some null string', fuzzy=True).date() to throw an exception, but it's returning the current date. Can someone show me how I can avoid getting the current date, if no date is found in the provided string? Thanks in advance. See the dateutil docs , specifically the parse function (emphasizes mine):

I am trying to print a recurrence rule as a string specified by iCalendar format (see RFC 5545 ). Im using python dateutils, in particular dateutil.rrule to create the recurrence rule and I want to print this as a string like: "RRULE:FREQ=DAILY;COUNT=5" Can anyone tell me if there is a method to achieve this? I think I'm using the labix dateutils btw. Many thanks! There is no method or function in the python-dateutil package to do this. See this bug for a patch that may help: https://bugs.launchpad.net/dateutil/+bug/943512 . Although this is written four years after the question was asked,

I'm using dateutil.parser.parse to format a date from a string. But now it mixes up the month and the day. I have a string that contains 05.01.2015 . After dateutil.parser.parse("05.01.2015") it returns: datetime.datetime(2015, 5, 1, 0, 0) I hoped the it would return (2015, 1, 5, 0, 0) How can I tell the code that the format is dd.mm.yyyy ? For the record, 25.01.2015 will be parsed as (2015, 1, 25, 0, 0) , as expected. Specify dayfirst=True : >>> dateutil.parser.parse("05.01.2015", dayfirst=True) datetime.datetime(2015, 1, 5, 0, 0) This gives precedence to the DD-MM-YYYY format instead of MM

This should be very simple, but I can't quite figure it out in Python. I want to have a function which takes two arguments, a UTC time in seconds and a zoneinfo name like 'Europe/Vienna' and returns the offset in seconds from local time and UTC for that point in time. In C it would be: /* ... code to to set local time to the time zone I want to compare against, not shown here. Then call function below to get difference vs localtime. Hardly an ideal solution, but just to demonstrate what I want in a "lingua franca" (C): */ int get_diff_vs_localtime(const time_t original_utc_time) { struct tm*

I'm trying to convert some date/times to UTC, which I thought would be dead simple in Python - batteries included, right? Well, it would be simple except that Python (2.6) doesn't include any tzinfo classes. No problem, a quick search turns up python-dateutil which should do exactly what I need. The problem is that I need to install it on Windows. I was able to upack the .tar.gz2 distribution using 7-zip, but now I'm left with a collection of files and no guidance on how to proceed. When I try to run setup.py I get the error "No module named setuptools". Stan Reshetnyk If dateutil is missing

Does anyone know why python's dateutil reverses the sign of the GMT offset when it parses the datetime field? Apparently this feature is a known outcome of not only dateutil but also other parsing functions. But this results in an INCORRECT datetime result unless a pre-processing hack is applied: from dateutil import parser jsDT = 'Fri Jan 02 2015 03:04:05.678910 GMT-0800' python_datetime = parser.parse(jsDT) print(python_datetime) >>> 2015-01-02 03:04:05.678910+08:00 jsDT = 'Fri Jan 02 2015 03:04:05.678910 GMT-0800' if '-' in jsDT: jsDT = jsDT.replace('-','+') elif '+' in jsDT: jsDT = jsDT

See the following code: import datetime import pytz fmt = '%Y-%m-%d %H:%M:%S %Z' d = datetime.datetime.now(pytz.timezone("America/New_York")) d_string = d.strftime(fmt) d2 = datetime.datetime.strptime(d_string, fmt) print d_string print d2.strftime(fmt) the output is 2013-02-07 17:42:31 EST 2013-02-07 17:42:31 The timezone information simply got lost in the translation. If I switch '%Z' to '%z', I get ValueError: 'z' is a bad directive in format '%Y-%m-%d %H:%M:%S %z' I know I can use python-dateutil , but I just found it bizzare that I can't achieve this simple feature in datetime and have to