From a timezone and a UTC time, get the difference in seconds vs local time at that point in time

Question

This should be very simple, but I can't quite figure it out in Python. I want to have a function which takes two arguments, a UTC time in seconds and a zoneinfo name like 'Europe/Vienna' and returns the offset in seconds from local time and UTC for that point in time.

In C it would be:

/* ... code to to set local time to the time zone I want to compare against,
   not shown here. Then call function below to get difference vs localtime.
   Hardly an ideal solution,
   but just to demonstrate what I want in a "lingua franca" (C): */


int get_diff_vs_localtime(const time_t original_utc_time)
{
    struct tm* ts;

    ts = localtime(&original_utc_time);

    return mktime(ts) - original_utc_time;
}

I guess my question really boils down to: "given an Olson timezone (example 'Europe/Stockholm') and a UTC time, what is the local time?

Answer 1

Assuming "UTC time in seconds" means POSIX timestamp. To convert it to Stockholm time:

from datetime import datetime
import pytz

tz = pytz.timezone('Europe/Stockholm')

utc_dt = datetime.utcfromtimestamp(posix_timestamp).replace(tzinfo=pytz.utc)
dt = tz.normalize(utc_dt.astimezone(tz))
print(dt.strftime('%Y-%m-%d %H:%M:%S %Z%z'))

tz.normalize() is unnecessary if the source timezone is UTC (like in this case).

A simpler alternative is to use fromtimestamp()'s tz parameter, to convert "seconds since the epoch" to local time:

from datetime import datetime
import pytz

tz = pytz.timezone('Europe/Stockholm')

dt = datetime.fromtimestamp(posix_timestamp, tz)
print(dt.strftime('%Y-%m-%d %H:%M:%S %Z%z'))

Both examples produce the same result.

If local machine uses "right" timezones then to convert POSIX timestamp received from an external source to UTC, an explicit formula could be used:

from datetime import datetime, timedelta
import pytz

utc_dt = datetime(1970, 1, 1, tzinfo=pytz.utc) + timedelta(seconds=posix_timestamp)

The latest formula may also support a larger date range (less likely issues with dates before 1970, after 2038 or 3000 years).

If the timestamp comes from the local "right" source then the first two examples should be used instead (they call "right" time.gmtime()).

Answer 2

You could use pytz and datetime to do something in the manner of:

from datetime import datetime
from pytz import timezone

def get_diff(now, tzname):
    tz = timezone(tzname)
    utc = timezone('UTC')
    utc.localize(datetime.now())
    delta =  utc.localize(now) - tz.localize(now)
    return delta

Which for the following example...

now = datetime.utcnow()
print(now)
tzname = 'Europe/Stockholm'
delta = get_diff(now, tzname)
print(delta)
now_in_stockholm = now + delta
print(now_in_stockholm)

... outputs:

2012-10-02 14:38:56.547475
2:00:00
2012-10-02 16:38:56.547475

Answer 3

I guess my question really boils down to: "given an Olson timezone (example 'Europe/Stockholm') and a UTC time, what is the local time?

If I understand your problem correctly:

from pytz import timezone
import datetime, time

tz = timezone('Asia/Kuwait')
utc_dt = datetime.datetime.utcfromtimestamp(time.time())
utc_dt + tz.utcoffset(utc_dt)

>>> tz.utcoffset(utc_dt).seconds
10800
>>> tz
<DstTzInfo 'Asia/Kuwait' LMT+3:12:00 STD>
>>> utc_dt + tz.utcoffset(utc_dt)
datetime.datetime(2012, 10, 2, 17, 13, 53, 504322)
>>> utc_dt
datetime.datetime(2012, 10, 2, 14, 13, 53, 504322)

Answer 4

This is pretty old, but I couldn't find a great answer, so here's what I came up with:

from datetime import datetime
local = datetime.now()
utc = datetime.utcnow()
int((local - utc).days * 86400 + round((local - utc).seconds, -1))

Returns:

-21600

because I am (currently) 21600 seconds (6 hours) behind UTC.

Note: the second date calculated (in this case UTC) needs to be rounded since there is a super small difference in time at each calculation.