parentheses

问题 I want to be able to pair up all parentheses in a string, if they aren't paired then then they get their index number and False. It seems like it is repeating some values over and over, i.e cl == pop[1]. I have tried to see where the problem is but I can't see it no matter how hard I try. So I'm asking if anyone help me to locate the error and maybe even improve my code ;) def check_parentheses(string): pending = 0 brackets = [] '''Checks if parens are paired, otherwise they are bad.'''

问题 I have multiple .txt files in a directory. Here is a sample of one of my .txt files: kkkkk; select xx("xE'", PUT(xx.xxxx.),"'") jdfjhf:jhfjj from xxxx_x_xx_L ; quit; /* 1.xxxxx FROM xxxx_x_Ex_x */ proc sql; ("TRUuuuth"); hhhjhfjs as fdsjfsj: select * from djfkjd to jfkjs ( SELECT abc AS abc1, abc_2_ AS efg, abc_fg, fkdkfj_vv, jjsflkl_ff, fjkdsf_jfkj FROM &xxx..xxx_xxx_xxE where ((xxx(xx_ix as format 'xxxx-xx') gff &jfjfsj_jfjfj.) and (xxx(xx_ix as format 'xxxx-xx') lec &jgjsd_vnv.)) ); jjjjjj

问题 I like method parameters enclosed in parenthesis, this is some Pascal nostalgia. When cleaning up code, if I find a method parameters without it I enclose them immediately. Today it caused my working code throwing errors although my syntax looks okay according to the documentation. Kernel.raise's documentation has this format: (Object) raise(exception[, string [, array]]) These are all working: > raise TypeError TypeError: TypeError > raise (TypeError) TypeError: TypeError > raise "Error

问题 I like method parameters enclosed in parenthesis, this is some Pascal nostalgia. When cleaning up code, if I find a method parameters without it I enclose them immediately. Today it caused my working code throwing errors although my syntax looks okay according to the documentation. Kernel.raise's documentation has this format: (Object) raise(exception[, string [, array]]) These are all working: > raise TypeError TypeError: TypeError > raise (TypeError) TypeError: TypeError > raise "Error

问题 I've been stuck trying to write a regular expression in Java to remove everything in the parenthesis below while preserving everything else. Note that the parenthesis can be nested, and I think this is why my pattern fails . Can someone help me? Below I tried: String testData = "1. d4 Nf6 2. c4 g6 3. Nc3 Bg7 4. e4 d6 5. Nf3 O-O 6. Be2 e5 7. dxe5 dxe5 8. Qxd8 Rxd8 9. Bg5 Nbd7 10. O-O-O {Diagram [#]} " + "Rf8 (10... Re8 11. Nb5 (11. Nd5)) (10... h6 11. Bxf6 Bxf6 12. Nd5) 11. Nd5 c6 (11... Nxe4

问题 I am analyzing analyzing some third party code and there is a "lazy" var statement that looks like this, and I would like to understand what the parenthesis are doing after the "computed property" curly braces: lazy var defaults:NSUserDefaults = { return .standardUserDefaults() }() The "return .standardUserDefaults()" is returning the NSUserDefaults instance object, so why add a () after the right curly brace? thanks 回答1: It means that its a block that is executed the first time defaults is

问题 In perl, parentheses are used for overriding precedence (as in most programming languages) as well as for creating lists. How can I tell if a particular pair of parens will be treated as a grouping construct or a one-element list? For example, I'm pretty sure this is a scalar and not a one-element list: (1 + 1) But what about more complex expressions? Is there an easy way to tell? 回答1: Three key principles are useful here: Context is king. The evaluation of your example (1 + 1) depends on the

问题 TSQL (as used in MS SQL Server 2000 and 2005) allows multiple JOIN clauses, one right after the other, no commas or parentheses needed. Try this in Access and it throws a fit: "Syntax error (missing operator) in query expression ... " From what I have been able to gather out in Google-land, Access SQL wants parentheses to group the JOIN clauses. Most advice on how to accomplish this is to use the design view or the query wizard, and let Access figure out where to put the parentheses (that are

问题 I want to match string ending with ')' . I use pattern : "[)]\b" or ".*[)]\b" It should match the string : x=main2.addMenu('Edit') But it doesn't work. What is wrong ? 回答1: The \b only matches a position at a word boundary. Think of it as a (^\w|\w$|\W\w|\w\W) where \w is any alphanumeric character and \W is any non-alphanumeric character. The parenthesis is non-alphanumeric so won't be matched by \b. Just match a parethesis, followed by the end of the string by using \)$ 回答2: If you want to

问题 I've searched near and far, and not found a plugin that can simply auto-close a set of parenthesis like Textmate. For example: Vim : (*manually close parens* → ) Textmate: (*Auto closes parens*) If you can describe a plugin for this, I will be very helpful. Thanks! 回答1: Try delimitMate: https://github.com/Raimondi/delimitMate Some plugins listed here as well.. Plus instructions on setting it up yourself: http://vim.wikia.com/wiki/Automatically_append_closing_characters 回答2: I use AutoPairs.