parentheses

问题 I've searched near and far, and not found a plugin that can simply auto-close a set of parenthesis like Textmate. For example: Vim : (*manually close parens* → ) Textmate: (*Auto closes parens*) If you can describe a plugin for this, I will be very helpful. Thanks! 回答1: Try delimitMate: https://github.com/Raimondi/delimitMate Some plugins listed here as well.. Plus instructions on setting it up yourself: http://vim.wikia.com/wiki/Automatically_append_closing_characters 回答2: I use AutoPairs.

问题 I have seen all over the internet to format a NEGATIVE double value with a parenthesis WITH a $ symbol ie. currency type. I am looking for a .NET format string, to format 12345.67 = 12,345.67 -12345.67 = (12,345.67) 回答1: MSDN on conditional formatting to the rescue! You can specify up to three different sections of your format string at once, separating them with semicolons. If you specify two format string sections, the first is used for positive and zero values while the second is used for

问题 In java, I'm trying to write a regular expression that will match a unit within a mathematical expression, i.e. things that are between operators What I mean is, in an expression like 1 + [1 + 2], the regex should match the first 1 and then the [1 + 2]. What I have is *[([-+]?\d+(\.\d+)?)(\[.+\])] * Of which ([-+]?\d+(\.\d+)?) is supposed to match any number and (\[.+\]) Is supposed to match something inside parentheses, but it isn't working...it's matching things like ']' and ' ' for some

问题 How can I remove nested parentheses recursively in Common LISP Such as (unnest '(a b c (d e) ((f) g))) => (a b c d e f g) (unnest '(a b)) => (a b) (unnest '(() ((((a)))) ())) => (a) Thanks 回答1: Here's what I'd do: (ql:quickload "alexandria") (alexandria:flatten list) That works mainly because I have Quicklisp installed already. 回答2: (defun flatten (l) (cond ((null l) nil) ((atom l) (list l)) (t (loop for a in l appending (flatten a))))) 回答3: I realize this is an old thread, but it is one of

问题 For example if the parenthesis/brackets is matching in the following: ({}) (()){}() () and so on but if the parenthesis/brackets is not matching it should return false, eg: {} ({}( ){}) (() and so on. Can you please check this code? Thanks in advance. public static boolean isParenthesisMatch(String str) { Stack<Character> stack = new Stack<Character>(); char c; for(int i=0; i < str.length(); i++) { c = str.charAt(i); if(c == '{') return false; if(c == '(') stack.push(c); if(c == '{') { stack

问题 For example if the parenthesis/brackets is matching in the following: ({}) (()){}() () and so on but if the parenthesis/brackets is not matching it should return false, eg: {} ({}( ){}) (() and so on. Can you please check this code? Thanks in advance. public static boolean isParenthesisMatch(String str) { Stack<Character> stack = new Stack<Character>(); char c; for(int i=0; i < str.length(); i++) { c = str.charAt(i); if(c == '{') return false; if(c == '(') stack.push(c); if(c == '{') { stack

问题 I have the following code: <?php $a = 1; $b = 2; echo "sum: " . $a + $b; echo "sum: " . ($a + $b); ?> When I execute my code I get: 2 sum: 3 Why does it fail to print the string "sum:" in the first echo? It seems to be fine when the addition is enclosed in parentheses. Is this weird behaviour anywhere documented? 回答1: Both operators the addition + operator and the concatenation . operator have the same operator precedence, but since they are left associative they get evaluated like the

问题 I have the following code: <?php $a = 1; $b = 2; echo "sum: " . $a + $b; echo "sum: " . ($a + $b); ?> When I execute my code I get: 2 sum: 3 Why does it fail to print the string "sum:" in the first echo? It seems to be fine when the addition is enclosed in parentheses. Is this weird behaviour anywhere documented? 回答1: Both operators the addition + operator and the concatenation . operator have the same operator precedence, but since they are left associative they get evaluated like the

问题 I'm exercising in javascript calculations using a combination of maths and variables and i'm finding a difficulty on using the right way parentheses. For example i want to do the following calculation [(4,95/ans2)-4,5]*100 where ans2 is a calculated variable. In the last field i get 45.000 and i should take - 4.046 ... if the input in the first and second fields was 2 + 2 <form name="Calcultor" Method="Get" id='form1'>First Number: <input type="text" name="first" size="35" id="first">+ Second

问题 I'm learning Python and, so far, I absolutely love it. Everything about it. I just have one question about a seeming inconsistency in function returns, and I'm interested in learning the logic behind the rule. If I'm returning a literal or variable in a function return, no parentheses are needed: def fun_with_functions(a, b): total = a + b return total However, when I'm returning the result of another function call, the function is wrapped around a set of parentheses. To wit: def lets_have