or-operator

Switch case with logical operator in C

由 倖福魔咒の 提交于 2019-12-19 18:59:20
问题 I am new to C and need help. My code is the following. #include<stdio.h> #include<conio.h> void main() { int suite=2; switch(suite) { case 1||2: printf("hi"); case 3: printf("byee"); default: printf("hello"); } printf("I thought somebody"); getche(); } I am working in Turbo C and the output is helloI thought somebody . There's no error message. Please, let me know how this is working. 回答1: case 1||2: Becomes true . so it becomes case 1: but the passed value is 2. so default case executed.

or is not valid C++ : why does this code compile?

由 与世无争的帅哥 提交于 2019-12-17 11:29:07
问题 Here is a very simple C++ application I made with QtCreator : int main(int argc, char *argv[]) { int a = 1; int b = 2; if (a < 1 or b > 3) { return 1; } return 0; } To me, this is not valid C++, as the keyword or is not a reserved keyword. But if I compile and run it, it works fine without any warnings ! The exit code is 0 and if I change b = 4, the exit code is 1 ! I'm not including anything to make sure there is no hidden define. This is really strange to me. Is this something Qt is

Logical operator || in javascript, 0 stands for Boolean false?

由 China☆狼群 提交于 2019-12-17 07:39:15
问题 I happened to know the following code Here is the code, and very simple: var test = 0 || -1 ; console.log(test); then the output in the console is -1 and somehow i am really new into the javascript, all i think of is that the 0 stands for Boolean False in JS ,and so || operator seems to ignore the 0 and assign the value -1 to the variable so am i right ? i just want a confirm 回答1: || — expr1 || expr2 (Logical OR) Returns expr1 if it can be converted to true; otherwise, returns expr2. Thus,

If-branch for x == “N” or “No” always runs [duplicate]

由 最后都变了- 提交于 2019-12-11 14:09:45
问题 This question already has answers here : Closed 6 years ago . Possible Duplicate: Why does `letter==“A” or “a”` always evaluate to True? When I run this in my program, the question goes through, however no matter the answer, the "No" option always runs. If I switch the option order, the "Y" option will only run and it will always go straight to start. I'm sure I'm missing something simple, I just don't know what. infoconf = raw_input("Is this information correct? Y/N: ") if infoconf == "N" or

Python regular expression using the OR operator

由 社会主义新天地 提交于 2019-12-11 11:13:12
问题 I am trying to parse a large sample of text files with regular expressions (RE). I am trying to extract from these files the part of the text which contains 'vu' and ends with a newline '\n' . Patterns differ from one file to another, so I tried to look for combinations of RE in my files using the OR operator. However, I did not find a way to automate my code so that the re.findall() function looks for a combination of RE. Here is an example of how I tried to tackle this issue, but apparently

Simplifying an “any of” check with or-operator in Ruby

由 末鹿安然 提交于 2019-12-10 15:25:51
问题 How to simplify the following check ?... if node[:base][:database][:adapter].empty? || node[:base][:database][:host].empty? || node[:base][:database][:database].empty? || node[:base][:database][:port].empty? to something like required_keys = { :adapter, :host, :database...etc...} required keys - node[:base][:database] == [] This syntax is a little off, but basically subtract the keys you have from the set of required keys. If you have all the required keys in your set, the result should be

Shortcut “or-assignment” (|=) operator in Java

由 ▼魔方 西西 提交于 2019-12-02 10:46:53
I have a long set of comparisons to do in Java, and I'd like to know if one or more of them come out as true. The string of comparisons was long and difficult to read, so I broke it up for readability, and automatically went to use a shortcut operator |= rather than negativeValue = negativeValue || boolean . boolean negativeValue = false; negativeValue |= (defaultStock < 0); negativeValue |= (defaultWholesale < 0); negativeValue |= (defaultRetail < 0); negativeValue |= (defaultDelivery < 0); I expect negativeValue to be true if any of the default<something> values are negative. Is this valid?

Using multiple boolean conditions in EL expression

由 无人久伴 提交于 2019-12-02 01:43:44
问题 I would like to know how can I combine multiple boolean coniditions in EL. I have following example and it is not working. <x:someComponent rendered="#{bean.condition1} or #{bean.condition2}"> How can I use "OR" and "AND" logical operators in EL? 回答1: The operator has to go inside the EL expression, not outside. You should see the #{...} as one big scope wherein various variables/conditions interact with each other. <x:someComponent rendered="#{bean.condition1 or bean.condition2}"> See also:

Using multiple boolean conditions in EL expression

由 北城以北 提交于 2019-12-01 23:46:06
I would like to know how can I combine multiple boolean coniditions in EL. I have following example and it is not working. <x:someComponent rendered="#{bean.condition1} or #{bean.condition2}"> How can I use "OR" and "AND" logical operators in EL? BalusC The operator has to go inside the EL expression, not outside. You should see the #{...} as one big scope wherein various variables/conditions interact with each other. <x:someComponent rendered="#{bean.condition1 or bean.condition2}"> See also: Our EL wiki page Conditionally displaying JSF components How to conditionally render plain HTML

Switch case with logical operator in C

由 假装没事ソ 提交于 2019-12-01 17:12:09
I am new to C and need help. My code is the following. #include<stdio.h> #include<conio.h> void main() { int suite=2; switch(suite) { case 1||2: printf("hi"); case 3: printf("byee"); default: printf("hello"); } printf("I thought somebody"); getche(); } I am working in Turbo C and the output is helloI thought somebody . There's no error message. Please, let me know how this is working. Jeyaram case 1||2: Becomes true . so it becomes case 1: but the passed value is 2. so default case executed. After that your printf("I thought somebody"); executed. do this: switch(suite){ case 1:/*fall through*/
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