or-operator

This question already has an answer here: How to test multiple variables against a value? 22 answers Please look at the code. I'm using a robot car to draw a letter and in this code, when I type b, it will still draw small case a. import create # Draw a: def drawa(): #create robot robot = create.Create(4) #switch robot to full mode robot.toFullMode() for i in range(1280): robot.go(20,30) robot.stop() robot.move(-40,20) # Draw b: def drawb(): #create robot robot = create.Create(4) #switch robot to full mode robot.toFullMode() robot.move(-100,20) for i in range(1270): robot.go(20,-30) robot.stop

I've seen this a lot: $fp = fopen($filepath, "w") or die(); But I can't seem to find any real documentation on this "or" syntax. It's obvious enough what it does, but can I use it anywhere? And must it be followed by die() ? Are there any caveats to using or when you could use something like if (file_exists($filepath)) $fp = fopen($filepath,"r"); else myErrMessage(); I know it seems like a silly question, but I can't find any hard and fast rules for this. Thanks. It's a logical operator and can be used in any logical expression. http://php.net/manual/en/language.operators.logical.php tacone

When I enter start then the program outputs the else function even though I fulfilled the criteria, I have tried with && as well and it still didn't work. Any answers would be appreciated. #include <iostream> #include <string> #include <windows.h> using namespace std; int main () { float timer; bool end; std::string input; end = false; cout << "Enter start then a number to count down from" << ".\n"; while (end == false){ cin >> input; if (input.find("end" || "End") != std::string::npos) end = true; else if (input.find("start" || "restart" || "Start" || "Restart") != std::string::npos) { cin >>

I'm creating a console app and using a switch statement to create a simple menu system. User input is in the form of a single character that displays on-screen as a capital letter. However, I do want the program to accept both lower- and upper-case characters. I understand that switch statements are used to compare against constants, but is it possible to do something like the following? switch(menuChoice) { case ('q' || 'Q'): //Some code break; case ('s' || 'S'): //More code break; default: break; } If this isn't possible, is there a workaround? I really don't want to repeat code. This way:

This is just fine: def foo a or b end This is also fine: def foo return a || b end This returns void value expression : def foo return a or b end Why? It doesn't even get executed; it fails the syntax check. What does void value expression mean? return a or b is interpreted as (return a) or b , and so the value of return a is necessary to calculate the value of (return a) or b , but since return never leaves a value in place (because it escapes from that position), it is not designed to return a valid value in the original position. And hence the whole expression is left with (some_void_value)

I'm trying to understand the behavior of or operator. Please see the below examples: $e = false || true; var_dump($e); Output is as expected: bool(true); $f = false or true; var_dump($f); Output is as expected: bool(false) . I understood this in a way that the = has a higher precedence than the Or , so that's why the $f is assigned to false . But the below code works quite opposite of what I thought. I thought that the $foo will be assigned to 5 and then compared to itself. But the $foo is getting assigned only when if the $foo is set that means it is checking if the $foo is assigned to

Here is a very simple C++ application I made with QtCreator : int main(int argc, char *argv[]) { int a = 1; int b = 2; if (a < 1 or b > 3) { return 1; } return 0; } To me, this is not valid C++, as the keyword or is not a reserved keyword. But if I compile and run it, it works fine without any warnings ! The exit code is 0 and if I change b = 4, the exit code is 1 ! I'm not including anything to make sure there is no hidden define. This is really strange to me. Is this something Qt is defining ? I didn't find anything in the documentation regarding that. Thomas Owens According to Wikipedia : C