kwargs

I need to do something like this: def func1(a, *args, b="BBB", **kwargs): print "a=%s b=%s args=%s kwargs=%s" % (a, b, args, kwargs) So that calling like this: func1("AAAA", h="HHH", j="JJJ") Produces the output: a=AAAA b=BBB args=() kwargs={'h': 'HHH', 'j': 'JJJ'} But it is not possible to put a default named argument after *args . ( SyntaxError: invalid syntax ) Why is this not allowed? Is there any readable way to implement this? The only way I know is b=kwargs.pop("b", "BBB") , but this is not very readable. I would prefer to have this in the function call definition, where it belongs: it

I would like to write a Python script that takes some necessary positional and some optional command-line arguments via argparse : Let's call the positional args a , b , c , and the optional arguments x , y , z . In my Python script, I would like to pass these args on to a function; specifically, I want a , b , c to be passed as *args , and x , y , z to be passed as **kwargs , the latter retaining their names. I would like to do this many times with different functions and different numbers of positional and optional arguments. Is there a neat, flexible, and/or pythonic way to do this? Here is

If I have a python function like so: def some_func(arg1, arg2, arg3=1, arg4=2): Is there a way to determine which arguments were passed by keyword from inside the function? EDIT For those asking why I need this, I have no real reason, it came up in a conversation and curiosity got the better of me. No, there is no way to do it in Python code with this signature -- if you need this information, you need to change the function's signature. If you look at the Python C API, you'll see that the actual way arguments are passed to a normal Python function is always as a tuple plus a dict -- i.e., the

Closed . This question needs details or clarity . It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post . Closed 2 years ago . I would like to my function func(*args, **kwargs) return one dictionary which contains all arguments I gave to it. For example: func(arg1, arg2, arg3=value3, arg4=value4) should return one dictionary like this: {'arg1': value1, 'arg2': value2, 'arg3': value3, 'arg4': value4 } You can use locals() or vars() : def func(arg1, arg2, arg3=3, arg4=4): print(locals()) func(1, 2) # {'arg3': 3, 'arg4': 4,

I have a little problem. I use argparse to parse my arguments, and it's working very well. To have the args, I do : p_args = parser.parse_args(argv) args = dict(p_args._get_kwargs()) But the problem with p_args is that I don't know how to get these arguments ordered by their position in the command line, because it's a dict. So is there any possibility to have the arguments in a tuple/list/ordered dict by their order in the command line? To keep arguments ordered, I use a custom action like this: import argparse class CustomAction(argparse.Action): def __call__(self, parser, namespace, values,

I am new to python and decorators and am stumped in writing a decorator which reports not only passed args and kwargs but ALSO the unchanged default kwargs. This is what I have so far. def document_call(fn): def wrapper(*args, **kwargs): print 'function %s called with positional args %s and keyword args %s' % (fn.__name__, args, kwargs) return fn(*args, **kwargs) return wrapper @document_call def square(n, trial=True, output=False): # kwargs are a bit of nonsense to test function if not output: print 'no output' if trial: print n*n square(6) # with this call syntax, the default kwargs are not

In the code below, I want to read obj.subject and place it into var subject, also read obj.body and place it into body . First I want to read the kwargs variables and search for keywords within the string to replace, if none exists then move on. How can I iterate through kwargs in Python? for key in kwargs: subject = str(obj.subject).replace('[%s]' % upper(key), kwargs[key]) for key in kwargs: body = str(obj.body).replace('[%s]' % upper(key), kwargs[key]) return (subject, body, obj.is_html) jterrace For Python 3 users: You can iterate through kwargs with .items() subject = obj.subject body =