kwargs

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 2 years ago . I would like to my function func(*args, **kwargs) return one dictionary which contains all arguments I gave to it. For example: func(arg1, arg2, arg3=value3, arg4=value4) should return one dictionary like this: {'arg1': value1, 'arg2': value2, 'arg3': value3, 'arg4': value4 } 回答1: You can use

问题 I am trying to initialize a Django formset with an addition parameter to pass on the forms in the formset. However when i initialize the formset with formset factory and pass the variable to it. the Kwargs is always empty forms.py from django.forms.formsets import BaseFormSet from django.forms.formsets import formset_factory class BaseCIFormSet(BaseFormSet): def __init__(self, *args, **kwargs): print kwargs self.grn_id = kwargs.pop('grn_id', None) super(BaseCIFormSet, self).__init__(*args, *

问题 I've been looking for a way to use **kwargs or *argv with argparse . I will from hard code to a dynamic way. Here is my hard code and a example how I will use it. def get_parser(): parser = argparse.ArgumentParser() parser.add_argument("-r", "--range", dest="r", nargs=8, help="AddRange Parameters") parser.add_argument("-p", "--parameters", dest="p", nargs=8, help="SetDefaults as Parameters") parser.add_argument("-r", "--range", dest="r", nargs=8, help="AddRange Parameters") return parser ""

问题 following this topic: allow users to "extend" API functions class Inspector: def __init__(self, passedFunc): self.passedFunc = passedFunc def __call__(self, *args, **kwargs): # Inspector needs to generate a list of arguments of the passed function and print them in *correct* order # now how to generate a list of arguments using data from both ''args' and 'kwargs'? # the user might keep default argument values, in which case both will be None, # he might only use args, in which case it is easy

问题 It seems to me that in Django's generic class-based views, the parameters request , args and kwargs travel from method to method, both as view instance attributes, as well as method arguments. What do I mean exactly? Class django.views.generic.base.View , defines the following function, called by its as_view method: def view(request, *args, **kwargs): self = cls(**initkwargs) if hasattr(self, 'get') and not hasattr(self, 'head'): self.head = self.get self.request = request self.args = args

问题 I got a pretty weird behaviour with the decorator library which is explained in the next code: from decorator import decorator @decorator def wrap(f, a, *args, **kwargs): print 'Decorator:', a, args, kwargs return f(a, *args, **kwargs) def mywrap(f): def new_f(a, *args, **kwargs): print 'Home made decorator:', a, args, kwargs return f(a, *args, **kwargs) return new_f @wrap def funcion(a, b, *args, **kwargs): pass @mywrap def myfuncion(a, b, *args, **kwargs): pass funcion(1, b=2) myfuncion(1,

问题 I am unable to figure out why this code doesn't work >>> my_list = [1,2,3,4,5] >>> my_set = {*my_list} File "<stdin>", line 1 my_set = {*my_list} ^ SyntaxError: invalid syntax *args is used in python to unpack list. My expectation was that the above operation would create a set but it didn't. Can *args and **kwargs in Python be only used to pass arguments as function ? I am aware of the set() function but curious why this syntax doesn't work. 回答1: Thanks to PEP0448, these days it does work,

问题 I'm pretty new to Python and was looking into using threading for some code via this post: Python - Using threads or a queue to iterate over a for loop that calls a function I was wondering why this simple example code errors out to Error: line 1: TypeError: file <maya console> line 4: __init__() got an unexpected keyword argument 'A' # My code: import threading class Test(threading.Thread): def __init__(self, **kwargs): super(Test, self).__init__( **kwargs) self.__dict__.update(**kwargs) A =

问题 I have a function that updates a record via an API. The API accepts a variety of optional keyword parameters: def update_by_email(self, email=None, **kwargs): result = post(path='/do/update/email/{email}'.format(email=email), params=kwargs) I have another function that uses the first function to update an individual field in the record: def update_field(email=None, field=None, field_value=None): """Encoded parameter should be formatted as <field>=<field_value>""" request = update_by_email

问题 In the code below, I want to read obj.subject and place it into var subject, also read obj.body and place it into body . First I want to read the kwargs variables and search for keywords within the string to replace, if none exists then move on. How can I iterate through kwargs in Python? for key in kwargs: subject = str(obj.subject).replace('[%s]' % upper(key), kwargs[key]) for key in kwargs: body = str(obj.body).replace('[%s]' % upper(key), kwargs[key]) return (subject, body, obj.is_html)