infix-notation

I can not solve this expression from postfix to infix. Please help me to understand in detail 5 x y - / x y + 3 ^ 7 / + postfix to infix: 5 x y - / x y + 3 ^ 7 / + STEP 5 x y - / A) 5xy-/ = 5 (x-y)/ = (5 / (x-y)) x y + B) x y + = (x + y) (x+y) 3 ^ B.1) (x + y) 3 ^ = ((x + y) ^ 3 ) Now, (5 / (x-y)) ((x + y) ^ 3 ) 7 / + = (5 / (x-y)) (((x + y) ^ 3 )/7 ) + = (5 / (x-y)) + (((x + y) ^ 3 )/7 ) POSTFIX and PREFIX are expression in which no brackets are used. Precedence of operator are decided in order of there appearance in expression, So to evaluate expression no need to search next operation to

My lecturer gave me an assignment to create a program to convert an infix expression to postfix using Stack. I've made the stack classes and some functions to read the infix expression. But this one function, called inToPos(char string[]) which is responsible to convert the inFix expression in the string inFix to the post fix expression in the string postFix using stacks, is creating a breakpoint. Can you guys help me out and tell me what I'm doing wrong? These are my codes that badly needs your help.. :) #include<stdio.h> #include<stdlib.h> #define MAX 15 #define true 1 #define false 0

Methods taking a single argument can be written as an infix operators in Scal. I.e. adding *(other:C) = foo(this, other) to class C, will allow us to write c1 * c2 instead of foo(c1,c2). But is there a way to define infix operators on existing classes that you cannot modify? E.g. if I wanted to write c1 + c2 instead of xor(c1,c2) , where c1,c2:Array[Byte] , I obviously cannot modify the Array-Class. I found this and tried implicit class Bytearray(a1:Array[Byte]) extends Anyval { def +(a2:Array[Byte]) = xor(a1,a2) } But that doesn't seem to work ( c1 + c2 ). Type mismatch, expected:String,

As I understood call-by-name parameters of a method, the corresponding argument expression will not be evaluated when passing it to the method, but only when (and if) the value of the parameter is used in the method body. In the following example, however, this is only true in the first two method calls, but not in the third one, although it should be a merely syntactical variation of the second case!? Why is the argument expression evaluated in the third method call? (I tested this code using Scala 2.11.7) class Node(x: => Int) class Foo { def :: (x: =>Int) = new Node(x) // a right

I have a prefix expression that only has the 4 binary operators(+,-,*,/) .A straight forward way to evaluate such an expression is to convert it to a postfix expression and then evaluate that expression. But I am looking for an algorithm that does this directly without converting it to any other expression ? Simple recursion: Evaluate(input): Read a token from input. If the token is a value: Return the value of the token If the token is a binary operator: Let first_argument = Evaluate(input) Let second_argument = Evaluate(input) Return apply(operator, first_argument, second_argument) Use a

I have a java class that converts infix expression to postfix. I have managed to make the class run without errors but it is not giving me the right output. The output is suppose to be in form : InToPost: converting expressions from infix to postfix... [A, +, B] [A, +, B, *, C] [A, +, B, *, C, +, D] [(, A, +, B, ), *, C] [(, A, +, B, ), /, (, C, -, D, )] [(, (, A, +, B, ), *, C, -, (, D, -, E, ), )] InToPost: emitting postfix expressions... A B + A B C * + A B C * + D + A B + C * A B + C D - / A B + C * D E - - But my output is: InToPost: converting expressions from infix to postfix... [A, +,

I'm trying to make a Haskell datatype a bit like a python dictionary, a ruby hash or a javascript object, in which a string is linked to a value, like so: data Entry t = Entry String t type Dictionary t = [Entry t] The above code works fine. However, I would like a slightly nicer constructor, so I tried defining it like this: data Entry t = String ~> t This failed. I tried this: data Entry t = [Char] ~> t Again, it failed. I know that ~ has special meaning in Haskell, and GHCi still permits the operator ~> , but I still tried one other way: data Entry t = [Char] & t And yet another failure due

I am looking for algorithm postfix to infix notation which will produce the minimum number of the parentheses. I have found that but it will produce many, many parentheses: http://tajendrasengar.blogspot.com/2011/09/postfix-to-infix-algorithm.html For example The input: <ONP>abcd*/+~ The result: <INF>~(a+b/(c*d)) What you need to do if you really want as few parentheses as possible, is similar to what the algorithm you linked to says. However... You should store an operator for each composite operand in the Stack . Namely, the last operator used in the operand. You could use a second Stack for