infix-notation

“Piping” output from one function to another using Python infix syntax

瘦欲@ 提交于 2019-11-28 20:24:21
I'm trying to replicate, roughly, the dplyr package from R using Python/Pandas (as a learning exercise). Something I'm stuck on is the "piping" functionality. In R/dplyr, this is done using the pipe-operator %>% , where x %>% f(y) is equivalent to f(x, y) . If possible, I would like to replicate this using infix syntax (see here ). To illustrate, consider the two functions below. import pandas as pd def select(df, *args): cols = [x for x in args] df = df[cols] return df def rename(df, **kwargs): for name, value in kwargs.items(): df = df.rename(columns={'%s' % name: '%s' % value}) return df

How to calculate expression in java?

只谈情不闲聊 提交于 2019-11-28 12:54:54
How to calculate user given Expression in java. E:g, if the given exp is 3*4+(5*6) how to calculate this. can anyone help me out. Paulpro I found this code after a quick google: import java.util.Stack; /** * Class to evaluate infix and postfix expressions. * * @author Paul E. Davis (feedback@willcode4beer.com) */ public class InfixPostfixEvaluator { /** * Operators in reverse order of precedence. */ private static final String operators = "-+/*"; private static final String operands = "0123456789"; public int evalInfix(String infix) { return evaluatePostfix(convert2Postfix(infix)); } public

How to make a right-associative infix operator?

扶醉桌前 提交于 2019-11-28 06:47:31
I have an associative operation >> . The problem is that its cost linearly depends on the size of its left operand. So an expression formed by a sequence of n applications of >> like a >> a >> a >> a >> a >> ... >> a it has quadratic cost in terms of n , because by default infix operators are left-associative . How to make it right-associative so that the cost of such an expression is kept linear in terms of n ? Petr Pudlák I found a solution. Scala reference says in section 6.12.3 Infix Operations : The associativity of an operator is determined by the operator’s last character. Operators

Scala - infix vs dot notation

感情迁移 提交于 2019-11-28 04:40:19
Is there a best practice for one over the other? I've been reading the Scala book by Odersky, et al. and it seems like infix is used for a lot of the Collections API functions, whereas dot is reserved for programmer-defined functions. I personally do not have any hard and fast rules for this, but I tend to use infix notation only with symbolic method names, and dot notation for alphanumeric ones. Infix notation makes it cumbersome to modify code later. Here are some examples. Imagine you have this line of code: xs filter { f } map { g } Suppose at some latter point in time you need to add a

How to calculate expression in java?

白昼怎懂夜的黑 提交于 2019-11-27 07:17:23
问题 How to calculate user given Expression in java. E:g, if the given exp is 3*4+(5*6) how to calculate this. can anyone help me out. 回答1: I found this code after a quick google: import java.util.Stack; /** * Class to evaluate infix and postfix expressions. * * @author Paul E. Davis (feedback@willcode4beer.com) */ public class InfixPostfixEvaluator { /** * Operators in reverse order of precedence. */ private static final String operators = "-+/*"; private static final String operands =

Handling extra operators in Shunting-yard

落爺英雄遲暮 提交于 2019-11-27 06:21:55
问题 Given an input like this: 3+4+ Algorithm turns it in to 3 4 + + I can find the error when it's time to execute the postfix expression. But, is it possible to spot this during the conversion? (Wikipedia article and internet articles I've read do not handle this case) Thank you 回答1: Valid expressions can be validated with a regular expression, aside from parenthesis mismatching. (Mismatched parentheses will be caught by the shunting-yard algorithm as indicated in the wikipedia page, so I'm

Scala - infix vs dot notation

∥☆過路亽.° 提交于 2019-11-27 00:27:14
问题 Is there a best practice for one over the other? I've been reading the Scala book by Odersky, et al. and it seems like infix is used for a lot of the Collections API functions, whereas dot is reserved for programmer-defined functions. 回答1: I personally do not have any hard and fast rules for this, but I tend to use infix notation only with symbolic method names, and dot notation for alphanumeric ones. Infix notation makes it cumbersome to modify code later. Here are some examples. Imagine you

When to use parenthesis in Scala infix notation

陌路散爱 提交于 2019-11-26 22:45:13
When programming in Scala, I do more and more functional stuff. However, when using infix notation it is hard to tell when you need parenthesis and when you don't. For example the following piece of code: def caesar(k:Int)(c:Char) = c match { case c if c isLower => ('a'+((c-'a'+k)%26)).toChar case c if c isUpper => ('A'+((c-'A'+k)%26)).toChar case _ => c } def encrypt(file:String,k:Int) = (fromFile(file) mkString) map caesar(k)_ The (fromFile(file) mkString) needs parenthesis in order to compile. When removed I get the following error: Caesar.scala:24: error: not found: value map def encrypt

Evaluating a string of simple mathematical expressions [closed]

帅比萌擦擦* 提交于 2019-11-26 21:17:51
Challenge Here is the challenge (of my own invention, though I wouldn't be surprised if it has previously appeared elsewhere on the web). Write a function that takes a single argument that is a string representation of a simple mathematical expression and evaluates it as a floating point value. A "simple expression" may include any of the following: positive or negative decimal numbers, + , - , * , / , ( , ) . Expressions use (normal) infix notation . Operators should be evaluated in the order they appear, i.e. not as in BODMAS , though brackets should be correctly observed, of course. The

How to make a right-associative infix operator?

大兔子大兔子 提交于 2019-11-26 20:07:53
问题 I have an associative operation >> . The problem is that its cost linearly depends on the size of its left operand. So an expression formed by a sequence of n applications of >> like a >> a >> a >> a >> a >> ... >> a it has quadratic cost in terms of n , because by default infix operators are left-associative. How to make it right-associative so that the cost of such an expression is kept linear in terms of n ? 回答1: I found a solution. Scala reference says in section 6.12.3 Infix Operations :