geometry

问题 The hypot function, introduced into C in the 1999 revision of the language, calculates the hypotenuse of a right triangle given the other sides as arguments, but with care taken to avoid the over/underflow which would result from the naive implementation as double hypot(double a, double b) { return sqrt(a*a + b*b); } I find myself with the need for companion functionality: given a side and the hypotenuse of a triangle, find the third side (avoiding under/overflow). I can think of a few ways

问题 The hypot function, introduced into C in the 1999 revision of the language, calculates the hypotenuse of a right triangle given the other sides as arguments, but with care taken to avoid the over/underflow which would result from the naive implementation as double hypot(double a, double b) { return sqrt(a*a + b*b); } I find myself with the need for companion functionality: given a side and the hypotenuse of a triangle, find the third side (avoiding under/overflow). I can think of a few ways

问题 The hypot function, introduced into C in the 1999 revision of the language, calculates the hypotenuse of a right triangle given the other sides as arguments, but with care taken to avoid the over/underflow which would result from the naive implementation as double hypot(double a, double b) { return sqrt(a*a + b*b); } I find myself with the need for companion functionality: given a side and the hypotenuse of a triangle, find the third side (avoiding under/overflow). I can think of a few ways

问题 In drawing apps such as Sketch, when you draw a vector, you can specify a custom corner radius for each point individually. For example, here is a 5 point vector, with the middle point's corner radius set to 17: (The top left and bottom right points have custom radii as well.) In Swift, I can draw paths using a UIBezierPath, but when I specify addLine , I'm only given an option to specify a point. I don't have the option to specify a corner radius. How do I give addLine a corner radius? It

问题 Background I want to add a model manager function that filters a queryset based on the proximity to coordinates. I found this blog posting with code that is doing precisely what I want. Code The snippet below seems to make use of geopy functions that have since been removed. It coarsely narrows down the queryset by limiting the range of latitude and longitude. # Prune down the set of all locations to something we can quickly check precisely rough_distance = geopy.distance.arc_degrees

问题 I'm trying to write a program that checks if a circle contains another circle, if a certain point is inside a circle, or the one I'm having trouble with, if a circle overlaps with another circle. import javafx.scene.shape.Circle; public class Problem10_11 { public static void main(String[] args) { //Create circle with certain parameters. Circle2D c1 = new Circle2D(2, 2, 5.5); //Create output which will be tested by all our methods. System.out.println("The area for circle 1 is " +c1.getArea()+

问题 I'm trying to write a program that checks if a circle contains another circle, if a certain point is inside a circle, or the one I'm having trouble with, if a circle overlaps with another circle. import javafx.scene.shape.Circle; public class Problem10_11 { public static void main(String[] args) { //Create circle with certain parameters. Circle2D c1 = new Circle2D(2, 2, 5.5); //Create output which will be tested by all our methods. System.out.println("The area for circle 1 is " +c1.getArea()+

问题 Suppose I have two sets of points, A and B, in 2D space. I want to know if there exists a single straight line that will have all points of A on one side and all points of B on the other, and if possible, find one such line. I found this question while searching but it is more of a "line of best fit" problem. Intuitively, I feel like it is a question regarding cross-products but I can't figure out how it can be done. 回答1: You could find the convex hull for each set of points, and then follow

问题 Suppose I have two sets of points, A and B, in 2D space. I want to know if there exists a single straight line that will have all points of A on one side and all points of B on the other, and if possible, find one such line. I found this question while searching but it is more of a "line of best fit" problem. Intuitively, I feel like it is a question regarding cross-products but I can't figure out how it can be done. 回答1: You could find the convex hull for each set of points, and then follow

问题 I have two sets of points in 3D space. I'd like to draw a line that runs through the center of both sets of points, and then find the angle from that line to each point. From there, I'll match points in the two sets up based on how close together their two angles are. I know how to find the center of each set of points (just average them all together) and I know how to match them up (even accounting for the fact they'll wrap around), but I don't know how to find the angle from the line to the