dereference

PHP dereference array elements

家住魔仙堡 提交于 2019-12-01 16:36:03
问题 I have 2 arrays. $result = array(); $row = array(); Row's elements are all references and is constantly changing. For each iteration of $row I want to copy the values of row into an entry of $result and not the references. I have found a few solutions but they all seem rather awful. $result[] = unserialize(serialize($row)); $result[] = array_flip(array_flip($row)); Both of the above work but seem like a lot of unnecessary and ugly code just to copy the contents of an array of references by

Can I get a python object from its memory address?

天大地大妈咪最大 提交于 2019-12-01 16:26:46
I'm learning how to use Qt with PyQt, and I have a QTabelView with a StandardItemModel I've populated the model successfully and hooked up the itemChanged signal to a slot. I'd l'd like to mess around with whatever object is returned in IPython, so currently I have the line: def itemChangedSlot(epw, item): new_data = item.data() print new_data print item which prints <PyQt4.QtGui.QStandardItem object at 0x07C5F930> <PyQt4.QtCore.QVariant object at 0x07D331F0> In the IPython session is it possible to get the object using this memory address? I'm not seeing anything on Google, maybe I don't have

-> usage in smart pointers

烂漫一生 提交于 2019-12-01 11:22:22
I have a simple smart pointer implementation shown in code snippet 1 below. And a dummy test class named Dummy in the 2nd snippet. The code snippet 3 shows how we can utilize this simple smart pointer to access the function foo(). My question is about the way we invoke the function foo() in class Dummy by using the -> operator. -> operator already returns a pointer to the raw pointer. So, I think, in order for us to be able to invoke function foo(), we need to perform a second -> operation on the returned raw pointer. However, many resources say that a single use of the -> operator is

-> usage in smart pointers

前提是你 提交于 2019-12-01 09:24:14
问题 I have a simple smart pointer implementation shown in code snippet 1 below. And a dummy test class named Dummy in the 2nd snippet. The code snippet 3 shows how we can utilize this simple smart pointer to access the function foo(). My question is about the way we invoke the function foo() in class Dummy by using the -> operator. -> operator already returns a pointer to the raw pointer. So, I think, in order for us to be able to invoke function foo(), we need to perform a second -> operation on

how to convert the perl hash string reference to perl hash reference

若如初见. 提交于 2019-12-01 08:21:14
HASH(0x991f0dc) so the above hash reference is stored as string in scalar variable,if we dereference it with "%" in the Perl program it throws error, Can't use string ("HASH(0x991f0dc) ") as a HASH ref while "strict refs" in use at tcpclient1.pl line 49, <GEN0> line 1 this above is throws from Perl program,i request solution,to convert back the hash string reference to Perl hash reference. You can't convert this back . The HASH(0x991f0dc) is not a hash reference. It is the string representation of a variable that contains a reference to a hash at that address. The error message you describe

how to convert the perl hash string reference to perl hash reference

我的梦境 提交于 2019-12-01 07:54:51
问题 HASH(0x991f0dc) so the above hash reference is stored as string in scalar variable,if we dereference it with "%" in the Perl program it throws error, Can't use string ("HASH(0x991f0dc) ") as a HASH ref while "strict refs" in use at tcpclient1.pl line 49, <GEN0> line 1 this above is throws from Perl program,i request solution,to convert back the hash string reference to Perl hash reference. 回答1: You can't convert this back . The HASH(0x991f0dc) is not a hash reference. It is the string

Pointers on Objective-c

孤人 提交于 2019-12-01 07:47:50
From what I understand (and please correct me if I'm wrong): int x, count = 10; int *hello; hello = &count; x = *hello; Here the variables x and count are declared to be of type integer. Additionally, the variable count is assigned the value of 10. hello is a pointer to type integer. hello is then assigned the address of count. In order to access the value of count, hello must have an asterisk in front of it, ie, *hello. So, x is assigned the value of whatever is in count and in this case, 10. However... Fraction *myFraction = [[Fraction alloc] init]; [myFraction someMethod]; Here, if I

char and char* (pointer)

两盒软妹~` 提交于 2019-12-01 04:01:32
I would like to understand how pointers work, so i created this small program. first of all i create a p pointer, which points to a char. The first question is at this point. If i create a pointer, the value of it is a memoryaddress (if i point it to a non-pointer object), but this time it is "haha" in my example. Why does it work this way in char*? And how i can add value to it with cin >> p? My second question is that, i created a q char, which has the value of the *p pointer at the point i created it. BUT its value and address are "h" too, but why? It must be the memory address of this char

Address of dereferenced pointer construct

北城以北 提交于 2019-12-01 02:05:02
问题 In unqlite c library I found following code: pObj = jx9VmReserveMemObj(&(*pVm),&nIdx); where pVm is: typedef struct jx9_vm jx9_vm; jx9_vm *pVm and function called is declared as: jx9_value * jx9VmReserveMemObj(jx9_vm *, sxu32 *); What for construct &(*pVm) is used in call instead of just pVm ? Is &(*pVm) equivalent to pVm ? 回答1: Quoting C11 , chapter §6.5.3.2, Address and indirection operators [...] If the operand is the result of a unary * operator, neither that operator nor the & operator

char and char* (pointer)

ε祈祈猫儿з 提交于 2019-12-01 01:34:15
问题 I would like to understand how pointers work, so i created this small program. first of all i create a p pointer, which points to a char. The first question is at this point. If i create a pointer, the value of it is a memoryaddress (if i point it to a non-pointer object), but this time it is "haha" in my example. Why does it work this way in char*? And how i can add value to it with cin >> p? My second question is that, i created a q char, which has the value of the *p pointer at the point i