dereference

Quick and simple question. I kind of understand what the Namespace Alias qualifier does, it's for accessing members in a namespace, however so does the dereferencing operator. I am really baffled as to the difference in this situation, why you would use one over the other, or how they each accomplish the same thing. using colAlias = System.Collections; namespace myns { class TestApp { static void Main() { colAlias.Hashtable test = new colAlias.Hashtable(); colAlias::Hashtable test1 = new colAlias::Hashtable(); } } } This is a corner case :: (like the @ prefix) is there to deal with the fairly

I am trying to pass contextInfo of type UnsafeMutablePointer<Void> to UISaveVideoAtPathToSavedPhotosAlbum and use it in the callback function. For some reason I am unable to access contextInfo as a string using UnsafePointer<String>(x).memory when I am in the callback function. I am pretty sure it is something simple I am missing but have spent way to many hours trying to figure this out. Below is some code that I have tried. The following code works. var testStr:String = "hello" takesAMutableVoidPointer(&testStr) func takesAMutableVoidPointer(x: UnsafeMutablePointer<Void>){ var pStr:String =

I'm not sure if this is a proper programming question, but it's something that has always bothered me, and I wonder if I'm the only one. When initially learning C++, I understood the concept of references, but pointers had me confused. Why, you ask? Because of how you declare a pointer. Consider the following: void foo(int* bar) { } int main() { int x = 5; int* y = NULL; y = &x; *y = 15; foo(y); } The function foo(int*) takes an int pointer as parameter. Since I've declared y as int pointer, I can pass y to foo , but when first learning C++ I associated the * symbol with dereferencing, as such

Possible Duplicate: C++: ptr->hello(); /* VERSUS */ (*ptr).hello(); Too bad I can't google this... Could someone explain or point me to where I can find the difference between these two? I understand * is a dereferencing operator, what about the -> ? What's the difference? a->b is a syntactic sugar for (*a).b The only special case is the object operator-> which is called when -> is used on an object. It can be used to "simulate" the object is a pointer ( as with smart references ) In the absence of overloading operator-> , p->x is equivalent to (*p).x 来源： https://stackoverflow.com/questions

I have 2 arrays. $result = array(); $row = array(); Row's elements are all references and is constantly changing. For each iteration of $row I want to copy the values of row into an entry of $result and not the references. I have found a few solutions but they all seem rather awful. $result[] = unserialize(serialize($row)); $result[] = array_flip(array_flip($row)); Both of the above work but seem like a lot of unnecessary and ugly code just to copy the contents of an array of references by value, instead of copying the references themselves. Is there a cleaner way to accomplish this? If not