channel

Multiple receivers on a single channel. Who gets the data?

两盒软妹~` 提交于 2019-11-30 16:52:47
问题 Unbuffered channels block receivers until data is available on the channel. It's not clear to me how this blocking behaves with multiple receivers on the same channel (say when using goroutines). I am sure they would all block as long as there is no data sent on that channel. But what happens once I send a single value to that channel? Which receiver/goroutine will get the data and therefore unblock? All of them? The first in line? Random? 回答1: A single random (non-deterministic) one will

Is it possible to integrate youtube channel in android?

不问归期 提交于 2019-11-30 15:51:58
I have the code for integrating YouTube videos in android. What I want is to create a listview which lists different channels, and when user clicks on a channel it shows all the videos for that channel. By this way when a new video is loaded in a channel it will automatically be available in my app also. Is it possible to integrate YouTube channel in android? Yes! Check out the Android Youtube Player API and the YouTube API. Android Player: https://developers.google.com/youtube/android/player/ YouTube API: https://developers.google.com/youtube/ YouTube Player API Sample: (sample folder in zip)

Is it possible to integrate youtube channel in android?

断了今生、忘了曾经 提交于 2019-11-30 14:23:19
问题 I have the code for integrating YouTube videos in android. What I want is to create a listview which lists different channels, and when user clicks on a channel it shows all the videos for that channel. By this way when a new video is loaded in a channel it will automatically be available in my app also. Is it possible to integrate YouTube channel in android? 回答1: Yes! Check out the Android Youtube Player API and the YouTube API. Android Player: https://developers.google.com/youtube/android

Java NIO - Memory mapped files

匆匆过客 提交于 2019-11-30 14:14:52
I recently came across this article which provided a nice intro to memory mapped files and how it can be shared between two processes. Here is the code for a process that reads in the file: import java.io.File; import java.io.FileNotFoundException; import java.io.IOException; import java.io.RandomAccessFile; import java.nio.MappedByteBuffer; import java.nio.channels.FileChannel; public class MemoryMapReader { /** * @param args * @throws IOException * @throws FileNotFoundException * @throws InterruptedException */ public static void main(String[] args) throws FileNotFoundException, IOException,

Cannot move out of captured outer variable in an `Fn` closure

北慕城南 提交于 2019-11-30 11:20:01
I'm trying to figure out how to send a function through a channel, and how to avoid extra cloning in order to execute the function at the other end. If I remove the extra cloning operation inside the closure, I get the following error: error: cannot move out of captured outer variable in an 'Fn' closure Ignoring the fact that this code does absolutely nothing, and makes use of a global mutable static Sender<T> , it represents what I'm trying to achieve while giving the proper compiler errors. This code is not meant to be ran , just compiled. use std::ops::DerefMut; use std::sync::{Arc, Mutex};

How does make(chan bool) behave differently from make(chan bool, 1)?

拈花ヽ惹草 提交于 2019-11-30 08:52:42
My question arises from trying to read a channel, if I can, or write it, if I can, using a select statement. I know that channels specified like make(chan bool, 1) are buffered, and part of my question is what is the difference between that, and make(chan bool) -- which this page says is the same thing as make(chan bool, 0) --- what is the point of a channel that can fit 0 values in it? See playground A : chanFoo := make(chan bool) for i := 0; i < 5; i++ { select { case <-chanFoo: fmt.Println("Read") case chanFoo <- true: fmt.Println("Write") default: fmt.Println("Neither") } } A output:

Is it possible to use Go's buffered channel as a thread-safe queue?

久未见 提交于 2019-11-30 08:06:14
问题 I want to find a queue structure (a data container) whose elements must be first-in-first-out. It is important for me that the structure must be thread-safe. I'm going to use this data container as something like a task or connection pool. I know a buffered channel is thread-safe, but I wonder if it works as FIFO, especially in a concurrent situation. And if it is possible to use buffered channel as a thread-safe queue, do I need to worry about its efficiency? 回答1: I'm pretty sure that

How to embed a YouTube channel into a webpage

本秂侑毒 提交于 2019-11-30 05:55:13
问题 Can anyone suggest how I embed a youtube channel into a webpage - I am getting conflicting information from various sites, ideally using the custom player if possible? thanks 回答1: YouTube supports a fairly easy to use iframe and url interface to embed videos, playlists and all user uploads to your channel : https://developers.google.com/youtube/player_parameters For example this HTML will embed a player loaded with a playlist of all the videos uploaded to your channel. Replace YOURCHANNELNAME

Go channels and deadlock

帅比萌擦擦* 提交于 2019-11-30 00:34:19
I'm trying to understand the Go language. I tried to create two goroutines that chain the flow between them using two channels: func main() { c1 := make(chan int) c2 := make(chan int) go func() { for i := range c1{ println("G1 got", i) c2 <- i } }() go func() { for i := range c2 { println("G2 got", i) c1 <- i } }() c1 <- 1 time.Sleep(1000000000 * 50) } As expected this code prints: G1 got 1 G2 got 1 G1 got 1 G2 got 1 .... Until the main function exits. But if I send another value to one of the channels from main, it suddenly blocks: func main() { c1 := make(chan int) c2 := make(chan int) go

Explain: Don't communicate by sharing memory; share memory by communicating

醉酒当歌 提交于 2019-11-30 00:16:23
I wonder what is the most down to earth explanation of this famous quote: Don't communicate by sharing memory; share memory by communicating. (R. Pike) In The Go Memory Model I can read this: A send on a channel happens before the corresponding receive from that channel completes. (Golang Spec) There is also a dedicated golang article explaining the quote. And key contribution is a working example also by Andrew G. Well. Sometimes too much talking around .... I have derived from the Memory Spec quotation and also by looking at the working example this: After a goroutine1 sends (anything) to a