channel

Java JSch create channel to access remote server via HTTP(s)

不羁的心 提交于 2019-12-02 13:12:49
Using the code at http://www.jcraft.com/jsch/examples/StreamForwarding.java.html , I have tried to create code that uses JSch to connect to an SSH server, then use it to connect to a server in the Web and pass HTTP(s) requests to the server, basically using the SSH server as a proxy. Here is what I have: //SSH server and credentials String host = "00.000.000.00"; String user = "login"; String password = "password"; int port = 22; //The host I want to send HTTP requests to - the remote host String remoteHost = "test.com"; int remotePort = 80; Properties config = new Properties(); config.put(

go routine for range over channels

邮差的信 提交于 2019-12-02 09:07:47
问题 I have been working in Golang for a long time. But still I am facing this problem though I know the solution to my problem. But never figured out why is it happening. For example If I have a pipeline situation for inbound and outbound channels like below: package main import ( "fmt" ) func main() { for n := range sq(sq(gen(3, 4))) { fmt.Println(n) } fmt.Println("Process completed") } func gen(nums ...int) <-chan int { out := make(chan int) go func() { for _, n := range nums { out <- n } close

How can I tell if another app has registered an IPC Remoting channel?

别来无恙 提交于 2019-12-01 18:14:39
问题 So I have an application which has a .NET API available. Their API library communicates with their main application through .NET remoting calls. In order to use the API, the application must be up and running already. So, I have an instance where I need to programmatically start the application and then instantiate one of the API objects, which attempts to open an IPC remoting channel to the main app. The problem is, after I start the process, there are a few seconds between startup and when

How can I tell if another app has registered an IPC Remoting channel?

 ̄綄美尐妖づ 提交于 2019-12-01 18:00:24
So I have an application which has a .NET API available. Their API library communicates with their main application through .NET remoting calls. In order to use the API, the application must be up and running already. So, I have an instance where I need to programmatically start the application and then instantiate one of the API objects, which attempts to open an IPC remoting channel to the main app. The problem is, after I start the process, there are a few seconds between startup and when the application registers the channel. If I try to instantiate an API object before the channel is

Shutdown “worker” go routine after buffer is empty

送分小仙女□ 提交于 2019-12-01 11:25:15
I want my go routine worker ( ProcessToDo() in the code below) to wait until all "queued" work is processed before shutting down. The worker routine has a "to do" channel (buffered), through which work is sent to it. And it has a "done" channel to tell it to start shutdown. The documentation says that the select on the channels will pick a "pseudo-random value" if more than one of the selects are met... which means the shutdown (return) is being triggered before all the buffered work is completed. In the code sample below, I want all 20 messages to print... package main import ( "time" "fmt" )

Shutdown “worker” go routine after buffer is empty

我怕爱的太早我们不能终老 提交于 2019-12-01 08:42:26
问题 I want my go routine worker ( ProcessToDo() in the code below) to wait until all "queued" work is processed before shutting down. The worker routine has a "to do" channel (buffered), through which work is sent to it. And it has a "done" channel to tell it to start shutdown. The documentation says that the select on the channels will pick a "pseudo-random value" if more than one of the selects are met... which means the shutdown (return) is being triggered before all the buffered work is

Is there any way to make Go's channels behave like a stack

允我心安 提交于 2019-12-01 08:39:27
Go channels by default behave like a queue as far as I can tell, first in first out. Is there any way to change them to work last in first out? Basically I am doing a search and want to do DFS instead of BFS for memory constraints. No, this is not possible - channels are always FIFO. You could use package container/heap . 来源: https://stackoverflow.com/questions/17755222/is-there-any-way-to-make-gos-channels-behave-like-a-stack

WCF client proxy initialization

☆樱花仙子☆ 提交于 2019-12-01 04:09:47
I am consuming a WCF service and created its proxy using the VS 2008 service reference. I am looking for the best pattern to call WCF service method Should I create the client proxy instance every time I call the service method and close the client as soon as I am done with that? When I profiled my client application, I could see that it is taking lot of time to get the Channel while initializing the proxy client Should I use a Singleton pattern for the client proxy so that I can use the only once instance and get rid of the re-initializing overhead? Is there any hidden problem with this

WCF client proxy initialization

為{幸葍}努か 提交于 2019-12-01 02:12:32
问题 I am consuming a WCF service and created its proxy using the VS 2008 service reference. I am looking for the best pattern to call WCF service method Should I create the client proxy instance every time I call the service method and close the client as soon as I am done with that? When I profiled my client application, I could see that it is taking lot of time to get the Channel while initializing the proxy client Should I use a Singleton pattern for the client proxy so that I can use the only

Open Youtube Channel calling YouTube App (Android)

本小妞迷上赌 提交于 2019-11-30 21:08:21
问题 I want to open YouTube App showing an specific channel, but this only execute the browser. try { Intent intent = new Intent(Intent.ACTION_VIEW); intent.setData(Uri.parse("http://www.youtube.com/"+channel)); startActivity(intent); } catch (Exception e) { startActivity(new Intent(Intent.ACTION_VIEW,Uri.parse("http://www.youtube.com/"+channel))); } I want to show this: 回答1: Do research on library called YouTubeAndroidPlayerApi. This piece of code does exactly what you want. Intent intent =