Avoiding the infamous “eval(parse())” construct

徘徊边缘 提交于 2019-11-26 13:58:58

问题


Ok, so I'm running some loops to process data stored in list objects. Ever mindful of the infamous fortune admonishment not to use eval(parse(mystring)), I came up with this:

Rgames> bar
$foo
$foo$fast
[1] 1 2 3 4 5

$foo$slow
[1]  6  7  8  9 10


$oof
$oof[[1]]
[1]  6  7  8  9 10

$oof[[2]]
[1] 1 2 3 4 5


Rgames> rab<-'bar'
Rgames> do.call('$',list(as.name(rab),'oof'))
[[1]]
[1]  6  7  8  9 10

[[2]]
[1] 1 2 3 4 5

Typically I'd be selecting a list (of which bar is one such) and then one element of the list (e.g. oof) which contains my data. The code above does the same thing as eval(parse(text=paste(rab,'$','oof',sep=''))) .
I'm doing all this specifically because I want to use the lists' names rather than [[x]] notation as a safety mechanism (because not all list objects have their contents in the same order).

Should I stick with the advice from DWin in R: eval(parse(...)) is often suboptimal ?


回答1:


Using get and [[:

bar <- list(foo = list(fast = 1:5, slow = 6:10),
            oof = list(6:10, 1:5))

rab <- 'bar'

get(rab)[['oof']]
# [[1]]
# [1]  6  7  8  9 10
# 
# [[2]]
# [1] 1 2 3 4 5



回答2:


If the name of your top list is going to change and be accessed by a variable with the name then it is best to put those lists into another list, then you can access the list you want using [[. Also read fortune(312) and the help on ?'[['.

You can then access the pieces in a different ways (detailed on the help page ?'[[').

mylist <- list()
mylist$bar <- bar

mylist[[rab]][['oof']]
#or
mylist[[ c(rab,'oof') ]]


来源:https://stackoverflow.com/questions/13647046/avoiding-the-infamous-evalparse-construct

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!