Multithreading: do I need protect my variable in read-only method?

六眼飞鱼酱① 提交于 2019-12-01 04:00:43

Yes, unless you can guarantee that changes to the underlying variable counter are atomic, you need the mutex.

Classic example, say counter is a two-byte value that's incremented in (non-atomic) stages:

add 1 to lower byte
if lower byte is 0:
    add 1 to upper byte

and the initial value is 255.

If another thread comes in anywhere between the lower byte change and the upper byte change, it will read 0 rather than the correct 255 (pre-increment) or 256 (post-increment).

In terms of what data types are atomic, the latest C++ standard defines them in the <atomic> header.

If you don't have C++11 capabilities, then it's down to the implementation what types are atomic.

Yes, you would need to lock the read as well in this case.

There are several alternatives -- a lock is quite heavy here. Atomic operations are the most obvious (lock-free). There are also other approaches to locking in this design -- the read write lock is one example.

Yes, I believe that you do need to lock the read as well. But since you are using C++11 features, why don't you use std::atomic<int> counter; instead?

You cant gaurantee that multiple threads wont modify your variable at the same time. and if such a situation occurs your variable will be garbled or program might crash. In order to avoid such cases its always better and safer to make the program thread safe.

You can use the synchronization techinques available like: Mutex, Lock, Synchronization attribute(available for MS c++)

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!