Close urllib2 connection

Question

I'm using urllib2 to load files from ftp- and http-servers.

Some of the servers support only one connection per IP. The problem is, that urllib2 does not close the connection instantly. Look at the example-program.

from urllib2 import urlopen
from time import sleep

url = 'ftp://user:pass@host/big_file.ext'

def load_file(url):
    f = urlopen(url)
    loaded = 0
    while True:
        data = f.read(1024)
        if data == '':
            break
        loaded += len(data)
    f.close()
    #sleep(1)
    print('loaded {0}'.format(loaded))

load_file(url)
load_file(url)

The code loads two files (here the two files are the same) from an ftp-server which supports only 1 connection. This will print the following log:

loaded 463675266
Traceback (most recent call last):
  File "conection_test.py", line 20, in <module>
    load_file(url)
  File "conection_test.py", line 7, in load_file
    f = urlopen(url)
  File "/usr/lib/python2.6/urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "/usr/lib/python2.6/urllib2.py", line 391, in open
    response = self._open(req, data)
  File "/usr/lib/python2.6/urllib2.py", line 409, in _open
    '_open', req)
  File "/usr/lib/python2.6/urllib2.py", line 369, in _call_chain
    result = func(*args)
  File "/usr/lib/python2.6/urllib2.py", line 1331, in ftp_open
    fw = self.connect_ftp(user, passwd, host, port, dirs, req.timeout)
  File "/usr/lib/python2.6/urllib2.py", line 1352, in connect_ftp
    fw = ftpwrapper(user, passwd, host, port, dirs, timeout)
  File "/usr/lib/python2.6/urllib.py", line 854, in __init__
    self.init()
  File "/usr/lib/python2.6/urllib.py", line 860, in init
    self.ftp.connect(self.host, self.port, self.timeout)
  File "/usr/lib/python2.6/ftplib.py", line 134, in connect
    self.welcome = self.getresp()
  File "/usr/lib/python2.6/ftplib.py", line 216, in getresp
    raise error_temp, resp
urllib2.URLError: <urlopen error ftp error: 421 There are too many connections from your internet address.>

So the first file is loaded and the second fails because the first connection was not closed.

But when i use sleep(1) after f.close() the error does not occurr:

loaded 463675266
loaded 463675266

Is there any way to force close the connection so that the second download would not fail?

Answer 1

The cause is indeed a file descriptor leak. We found also that with jython, the problem is much more obvious than with cpython. A colleague proposed this sollution:

 

    fdurl = urllib2.urlopen(req,timeout=self.timeout)
    realsock = fdurl.fp._sock.fp._sock** # we want to close the "real" socket later 
    req = urllib2.Request(url, header)
    try:
             fdurl = urllib2.urlopen(req,timeout=self.timeout)
    except urllib2.URLError,e:
              print "urlopen exception", e
    realsock.close() 
    fdurl.close()

The fix is ugly, but does the job, no more "too many open connections".

Answer 2

Biggie: I think it's because the connection is not shutdown().

Note close() releases the resource associated with a connection but does not necessarily close the connection immediately. If you want to close the connection in a timely fashion, call shutdown() before close().

You could try something like this before f.close():

import socket
f.fp._sock.fp._sock.shutdown(socket.SHUT_RDWR)

(And yes.. if that works, it's not Right(tm), but you'll know what the problem is.)

Answer 3

as for Python 2.7.1 urllib2 indeed leaks a file descriptor: https://bugs.pypy.org/issue867

Answer 4

Alex Martelli answers to the similar question. Read this : should I call close() after urllib.urlopen()?

In a nutshell:

import contextlib

with contextlib.closing(urllib.urlopen(u)) as x:
    # ...