Fancybox popup once time for session

I have a popup with fancybox that appear at load page.

I need to show the popup once a time, if the user change page and back on the page with popup doesn't reveal a second time.

I've read that could be use a cookie plug in (https://github.com/carhartl/jquery-cookie) but i dont understant how integrate in this code...

I have a simple site in html/css.

This is the code:

<!DOCTYPE html>

<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title></title>
<script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js">     </script>
<script type="text/javascript" src="jquery.fancybox-1.3.1.js"></script>
<link rel="stylesheet" type="text/css" href="jquery.fancybox-1.3.1.css" media="screen" />
<script src="jquery.cookie.js"></script>


<script type="text/javascript">
function openFancybox() {
setTimeout(function () {
    $('#yt').trigger('click');
}, 500);
};
$(document).ready(function () {
var visited = $.cookie('visited');
if (visited == 'yes') {
    return false; // second page load, cookie active
} else {
    openFancybox(); // first page load, launch fancybox
}
$.cookie('visited', 'yes', {
    expires: 7 // the number of days cookie  will be effective
});
$("#yt").click(function() {
            $.fancybox({
                    'padding'        : 0,
                    'autoScale'      : false,
                    'transitionIn'   : 'none',
                    'transitionOut'  : 'none',
                    'title'          : this.title,
                    'width'          : 680,
                    'height'         : 495,
                    'href'           : this.href.replace(new RegExp("watch\\?v=", "i"),  'v/'),
                    'type'           : 'swf',
                    'swf'            : {
                        'wmode'              : 'transparent',
                        'allowfullscreen'    : 'true'
                    }
                });
    return false;
});
});
</script>
</head>

<body onload='$("#yt").trigger("click");'>

  <a id="yt" href="https://www.youtube.com/watch?v=ROTYmNckBCw&amp;fs=1&amp;autoplay=1"><img  src="http://fancyapps.com/fancybox/demo/1_s.jpg" alt=""/></a>
</body>
</html>

For browser consistency, you may need to delay the fancybox load execution for the first time so try this code :

function openFancybox() {
    // launches fancybox after half second when called
    setTimeout(function () {
        $('#yt').trigger('click');
    }, 500);
};
$(document).ready(function () {
    var visited = $.cookie('visited'); // create the cookie
    if (visited == 'yes') {
        return false; // second page load, cookie is active so do nothing
    } else {
        openFancybox(); // first page load, launch fancybox
    };
    // assign cookie's value and expiration time
    $.cookie('visited', 'yes', {
        expires: 7 // the number of days the cookie will be effective
    });
    // your normal fancybox script
    $("#yt").click(function () {
        $.fancybox({
            // your fancybox API options
        });
        return false;
    });
});

See code at this JSFIDDLE

NOTES :

In order to see the cookie working, you may need to use jsfiddle's full screen mode http://jsfiddle.net/aVE9N/show/
I would advice you to update (at least) your fancybox version from v1.3.1 to v1.3.4
It's assumed you are loading properly the jQuery cookie plugin in your page

Using the jQuery cookie plugin you suggested:

$(document).ready(function() {
    if(typeof $.cookie('popupVideoPlayed') == 'undefined') {
        $.cookie('popupVideoPlayed', 'true'); // set a session cookie so it won't play again
        $('#yt').trigger('click');
    }
});

Remember to delete the inline body onload event handler.

来源：https://stackoverflow.com/questions/23431862/fancybox-popup-once-time-for-session

标签

javascript

jquery

popup

fancybox