Using discrete custom color in a plotly heatmap

故事扮演 提交于 2019-11-30 17:54:50

问题


I'm trying to generate a plotly heatmap, where I'd like the colors to be specified by a discrete scale.

Here's what I mean:

Generate data with 2 clusters and hierarchically cluster them:

require(permute)
set.seed(1)
mat <- rbind(cbind(matrix(rnorm(2500,2,1),nrow=25,ncol=500),matrix(rnorm(2500,-2,1),nrow=25,ncol=500)),
             cbind(matrix(rnorm(2500,-2,1),nrow=25,ncol=500),matrix(rnorm(2500,2,1),nrow=25,ncol=500)))
rownames(mat) <- paste("g",1:50,sep=".")
colnames(mat) <- paste("s",1:1000,sep=".")
hc.col <- hclust(dist(t(mat)))
dd.col <- as.dendrogram(hc.col)
col.order <- order.dendrogram(dd.col)
hc.row <- hclust(dist(mat))
dd.row <- as.dendrogram(hc.row)
row.order <- order.dendrogram(dd.row)
mat <- mat[row.order,col.order]

Brake the values in mat to intervals and set a color for each interval:

require(RColorBrewer)
mat.intervals <- cut(mat,breaks=6)
interval.mat <- matrix(mat.intervals,nrow=50,ncol=1000,dimnames=list(rownames(mat),colnames(mat)))
interval.cols <- brewer.pal(6,"Set2")
names(interval.cols) <- levels(mat.intervals)

Using ggplot2 I draw this heatmap this way (also having the legend specify the discrete colors and respective ranges):

require(reshape2)
interval.df <- reshape2::melt(interval.mat,varnames=c("gene","sample"),value.name="expr")
require(ggplot2)
ggplot(interval.df,aes(x=sample,y=gene,fill=expr))+
  geom_tile(color=NA)+theme_bw()+
  theme(strip.text.x=element_text(angle=90,vjust=1,hjust=0.5,size=6),panel.spacing=unit(0.025,"cm"),legend.key=element_blank(),plot.margin=unit(c(1,1,1,1),"cm"),legend.key.size=unit(0.25,"cm"),panel.border=element_blank(),strip.background=element_blank(),axis.ticks.y=element_line(size=0.25))+
  scale_color_manual(drop=FALSE,values=interval.cols,labels=names(interval.cols),name="expr")+
  scale_fill_manual(drop=FALSE,values=interval.cols,labels=names(interval.cols),name="expr")

which gives:

This is my attempt to generate it with plotly:

plot_ly(z=mat,x=colnames(mat),y=rownames(mat),type="heatmap",colors=interval.cols)

which gives:

The figures are not identical. In the ggplot2 figure the clusters are much more pronounced in contrast to the plotly figure.

Is there any way to parametrize the plotly command to give something more similar to the ggplot2 figure?

Also, is it possible to make the plotly legend discrete - similar to that in the ggplot2 figure?

Now suppose I want to facet the clusters. In the ggplot2 case I'd do:

require(dplyr)
facet.df <- data.frame(sample=c(paste("s",1:500,sep="."),paste("s",501:1000,sep=".")),facet=c(rep("f1",500),rep("f2",500)),stringsAsFactors=F)
interval.df <- left_join(interval.df,facet.df,by=c("sample"="sample"))
interval.df$facet <- factor(interval.df$facet,levels=c("f1","f2"))

And then plot:

ggplot(interval.df,aes(x=sample,y=gene,fill=expr))+facet_grid(~facet,scales="free",space="free",switch="both")+
  geom_tile(color=NA)+labs(x="facet",y="gene")+theme_bw()+
  theme(strip.text.x=element_text(angle=90,vjust=1,hjust=0.5,size=6),panel.spacing=unit(0.05,"cm"),plot.margin=unit(c(1,1,1,1),"cm"),legend.key.size=unit(0.25,"cm"),panel.border=element_blank(),strip.background=element_blank(),axis.ticks.y=element_line(size=0.25))+
  scale_color_manual(drop=FALSE,values=interval.cols,labels=names(interval.cols),name="expr")+
  scale_fill_manual(drop=FALSE,values=interval.cols,labels=names(interval.cols),name="expr")

Which gives:

So the clusters are separated by the panel.spacing and look even more pronounced. Is there any way to achieve this faceting with plotly?


回答1:


I was thinking initially the same thing, which is to down-sample the gradient, but instead forcing harsher transitions seems to do the trick at least to make the colors more pronounced.

interval.cols2 <- rep(interval.cols, each=1000)
plot_ly(z=mat,x=colnames(mat),y=rownames(mat),type="heatmap",colors=interval.cols2)




回答2:


Let's get a discrete colorscale

df_colors = data.frame(range=c(0:11), colors=c(0:11))
color_s <- setNames(data.frame(df_colors$range, df_colors$colors), NULL)
for (i in 1:12) {
  color_s[[2]][[i]] <- interval.cols[[(i + 1) / 2]]
  color_s[[1]][[i]] <-  i / 12 - (i %% 2) / 12
}

And get a nice colorbar by setting ticktext and squeezing it (len=0.2)

colorbar=list(tickmode='array', tickvals=c(1:6), ticktext=levels(mat.intervals), len=0.2)

All the code which needs to be added to your example

df_colors = data.frame(range=c(0:11), colors=c(0:11))
color_s <- setNames(data.frame(df_colors$range, df_colors$colors), NULL)

for (i in 1:12) {
  color_s[[2]][[i]] <- interval.cols[[(i + 1) / 2]]
  color_s[[1]][[i]] <-  i / 12 - (i %% 2) / 12
}


plot_ly(z=c(interval.df$expr), x=interval.df$sample, y=interval.df$gene, colorscale = color_s, type = "heatmap", hoverinfo = "x+y+z", colorbar=list(tickmode='array', tickvals=c(1:6), ticktext=levels(mat.intervals), len=0.2))



回答3:


Combining the answers of @Maximilian Peters and @R.S.:

Data:

require(permute)
set.seed(1)
mat <- rbind(cbind(matrix(rnorm(2500,2,1),nrow=25,ncol=500),matrix(rnorm(2500,-2,1),nrow=25,ncol=500)),
             cbind(matrix(rnorm(2500,-2,1),nrow=25,ncol=500),matrix(rnorm(2500,2,1),nrow=25,ncol=500)))
rownames(mat) <- paste("g",1:50,sep=".")
colnames(mat) <- paste("s",1:1000,sep=".")
hc.col <- hclust(dist(t(mat)))
dd.col <- as.dendrogram(hc.col)
col.order <- order.dendrogram(dd.col)
hc.row <- hclust(dist(mat))
dd.row <- as.dendrogram(hc.row)
row.order <- order.dendrogram(dd.row)
mat <- mat[row.order,col.order]

Colors:

require(RColorBrewer)
mat.intervals <- cut(mat,breaks=6)
interval.mat <- matrix(mat.intervals,nrow=50,ncol=1000,dimnames=list(rownames(mat),colnames(mat)))
require(reshape2)
interval.df <- reshape2::melt(interval.mat,varnames=c("gene","sample"),value.name="expr")
interval.cols <- brewer.pal(6,"Set2")
names(interval.cols) <- levels(mat.intervals)
interval.cols2 <- rep(interval.cols, each=ncol(mat))
color.df <- data.frame(range=c(0:(2*length(interval.cols)-1)),colors=c(0:(2*length(interval.cols)-1)))
color.df <- setNames(data.frame(color.df$range,color.df$colors),NULL)
for (i in 1:(2*length(interval.cols))) {
  color.df[[2]][[i]] <- interval.cols[[(i + 1) / 2]]
  color.df[[1]][[i]] <-  i/(2*length(interval.cols))-(i %% 2)/(2*length(interval.cols))
}

Plotting:

plot_ly(z=c(interval.df$expr),x=interval.df$sample,y=interval.df$gene,colors=interval.cols2,type="heatmap",colorscale=color.df,
        colorbar=list(tickmode='array',tickvals=c(1:6),ticktext=names(interval.cols),len=0.2,outlinecolor="white",bordercolor="white",borderwidth=5,bgcolor="white"))

It would be great if anyone can add:

  1. How to facet or create a narrow border between the facets.
  2. How to get the colorbar tick labels to appear exactly in the middle of each box in the colorbar


来源:https://stackoverflow.com/questions/42524450/using-discrete-custom-color-in-a-plotly-heatmap

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