Enumeration with raw values

问题

Why I can't define enumeration with raw values like this?

enum Edges : (Double, Double) {
    case TopLeft = (0.0, 0.0)
    case TopRight = (1.0, 0.0)
    case BottomLeft = (0.0, 1.0)
    case BottomRight = (1.0, 1.0)
}

回答1:

Because:

Raw values can be strings, characters, or any of the integer or floating-point number types.

But there is an alternative solution for you:

enum Edges {
    case TopLeft
    case TopRight
    case BottomLeft
    case BottomRight

    func getTuple() -> (Double, Double) {
        switch self {
        case .TopLeft:
            return (0.0, 0.0)
        case .TopRight:
            return (1.0, 0.0)
        case .BottomLeft:
            return (0.0, 1.0)
        case .BottomRight:
            return (1.0, 1.0)
        }
    }
}

let a = Edges.BottomLeft
a.getTuple() // returning (0, 1)

回答2:

A tuple cannot be a raw value type of enum. From The Swift Programming Language:

Raw values can be strings, characters, or any of the integer or floating-point number types.

You could create a custom getter though:

enum Edges {
    case TopLeft, TopRight, BottomLeft, BottomRight

    var rawValue: (Double, Double) {
        switch self {
            case .TopLeft: return (0, 0)
            case .TopRight: return (1, 0)
            case .BottomLeft: return (0, 1)
            case .BottomRight: return (1, 1)
        }
    }
}

来源：https://stackoverflow.com/questions/37488869/enumeration-with-raw-values