Error in terms.formula(formula) : '.' in formula and no 'data' argument

问题

I'm tring to use neuralnet for prediction.

Create some X:

x <- cbind(seq(1, 50, 1), seq(51, 100, 1))

Create Y:

y <- x[,1]*x[,2]

Give them a names

colnames(x) <- c('x1', 'x2')
names(y) <- 'y'

Make data.frame:

dt <- data.frame(x, y)

And now, I got error

model <- neuralnet(y~., dt, hidden=10, threshold=0.01)

error in terms.formula(formula) : '.' in formula and no 'data' argument

For example, in lm(linear model) this is worked.

回答1:

As my comment states, this looks like a bug in the non-exported function neuralnet:::generate.initial.variables. As a work around, just build a long formula from the names of dt, excluding y, e.g.

n <- names(dt)
f <- as.formula(paste("y ~", paste(n[!n %in% "y"], collapse = " + ")))
f

## gives
> f
y ~ x1 + x2

## fit model using `f`
model <- neuralnet(f, data = dt, hidden=10, threshold=0.01)

> model
Call: neuralnet(formula = f, data = dt, hidden = 10, threshold = 0.01)

1 repetition was calculated.

        Error Reached Threshold Steps
1 53975276.25     0.00857558698  1967

回答2:

Offering a simpler alternative to the previous answer, you can create a formula from names of dt using reformulate():

f <- reformulate(setdiff(colnames(dt), "y"), response="y")

reformulate() doesn't require the use of paste() and automatically adds the terms together.

来源：https://stackoverflow.com/questions/17794575/error-in-terms-formulaformula-in-formula-and-no-data-argument