问题
In an XML document, I have elements which share the same name, but the value of an attribute defines what type of data it is, and I want to select all of those elements which have a certain value from the document. Do I need to use XPath (and if so, could you suggest the right syntax) or is there a more elegant solution?
Here\'s some example XML:
<object>
<data type=\"me\">myname</data>
<data type=\"you\">yourname</data>
<data type=\"me\">myothername</data>
</object>
And I want to select the contents of all <data>
tags children of <object>
who\'s type is me
.
PS - I\'m trying to interface with the Netflix API using PHP - this shouldn\'t matter for my question, but if you want to suggest a good/better way to do so, I\'m all ears.
回答1:
Try this XPath:
/object/data[@type="me"]
So:
$myDataObjects = $simplexml->xpath('/object/data[@type="me"]');
And if object
is not the root of your document, use //object/data[@type="me"]
instead.
回答2:
I just made a function to do this for me; it only grabs the first result though. Your mileage may vary.
function query_attribute($xmlNode, $attr_name, $attr_value) {
foreach($xmlNode as $node) {
switch($node[$attr_name]) {
case $attr_value:
return $node;
}
}
}
Usage:
echo query_attribute($MySimpleXmlNode->Customer, "type", "human")->Name;
(For the XML below)
<Root><Customer type="human"><Name>Sam Jones</name></Customer></Root>
来源:https://stackoverflow.com/questions/992450/simplexml-selecting-elements-which-have-a-certain-attribute-value