PHP - Using strtotime with a UK date format (dd-mm-yy)

问题

Quite simply in PHP I have a date of 8th January 2011, in the format 08-01-11 - when I run this into strtotime and convert it back into a different date format, it reverts back to 1st August 2011 - not ideal!

Is there any easy way around this, rather than having to place everything into different arrays/variables and back again?

Thank you!

回答1:

strtotime() works with US dates only:

The function expects to be given a string containing a US English date format and will try to parse that format into a Unix timestamp.

You would have to either rearrange the date format or use date_parse_from_format() (PHP 5.3+) to parse the UK style string.

回答2:

The perfect solution would be for the US to use the correct date format in the first place... ;0)

I do this to get around it:

$date = "31/12/2012";
$bits = explode('/',$date);
$date = $bits[1].'/'.$bits[0].'/'.$bits[2];

$date is now strtotimeable

回答3:

From the PHP manual:

"Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed.

To avoid potential ambiguity, it's best to use ISO 8601 (YYYY-MM-DD) dates or DateTime::createFromFormat() when possible."

I replaced slashes with dashes and then strtotime worked as expected for UK dates.

来源：https://stackoverflow.com/questions/4163641/php-using-strtotime-with-a-uk-date-format-dd-mm-yy