I'm writing a PHP script that downloads a series of generated files (using wget) into a directory, and then zips then up, using the zip command.
The downloads work perfectly, and the zipping mostly works. I run the command:
zip -r /var/www/oraviewer/rgn_download/download/fcst_20100318_0319.zip /var/www/oraviewer/rgn_download/download/fcst_20100318_0319
which yields a zip file with all the downloaded files, but it contains the full /var/www/oraviewer/rgn_download/download/ directories, before reaching the fcst_20100318_0319/ directory.
I'm probably just missing a flag, or something small, from the zip command, but how do I get it to use fcst_20100318_0319/ as the root directory?
I don't think zip has a flag to do that. I think the only way is something like:
cd /var/www/oraviewer/rgn_download/download/ && \
zip -r fcst_20100318_0319.zip fcst_20100318_0319
(The backslash is just for clarity, you can remove it and put everything on one line.)
Since PHP is executing the command in a subshell, it won't change your current directory.
I have also get it worked by using this command
exec('cd '.$_SERVER['DOCUMENT_ROOT'].' && zip -r com.zip "./"');
cd /home/public_html/site/upload/ && zip -r sub_upload.zip sub_upload/
来源：https://stackoverflow.com/questions/2473115/command-to-zip-a-directory-using-a-specific-directory-as-the-root