Loop over two generator together

问题

I have two generators say A() and B(). I want to iterate over both the generators together. Something like:

for a,b in A(),B():    # I know this is wrong
    #do processing on a and b

One way is to store the results of both the functions in lists and then loop over the merged list. Something like this:

resA = [a for a in A()]
resB = [b for b in B()]
for a,b in zip(resA, resB):
    #do stuff

If you are wondering, then yes both the functions yield equal number of value.

But I can't use this approach because A()/B() returns so many values. Storing them in a list would exhaust the memory, that's why I am using generators.

Is there any way to loop over both the generators at once?

回答1:

You were almost there. In Python 3, just pass the generators to zip():

for a, b in zip(A(), B()):

zip() takes any iterable, not just lists. It will consume the generators one by one.

In Python 2, use itertools.izip():

from itertools import izip

for a, b in izip(A(), B()):

As an aside, turning a generator into a list is as simple as list(generator); no need to use a list comprehension there.

回答2:

Sounds like you want itertools.izip:

from itertools import izip

for a, b in izip(A(), B()):

From the docs:

Like zip() except that it returns an iterator instead of a list.

So this way you never create a list, either of A(), B() or the izip().

Note that in Python 3's basic zip is like Python 2.x's itertools.izip.

回答3:

You can use the zip function to transform the two lists generated into an list of tuples, so you can use the way you want:

for a,b in zip(A(), B()):
    pass

来源：https://stackoverflow.com/questions/20910213/loop-over-two-generator-together

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python

loops

for-loop

generator

yield