问题
I have 3 threads 1st printing A 2nd printing B 3rd printing C
I want to print in sequence A B C A B C A B C and so on.....
So I wrote the program below, but I am not able to achieve the same. I am aware of the problem that when status=1 at that time say for example B1 and C1 thread are waiting and when I do notifyAll() both waiting thread wake up and depending on CPU allocation it might print B or C.
in this case I want only B to be printed after A.
what modification I need to do.
public class NotifyAllExample {
int status=1;
public static void main(String[] args) {
NotifyAllExample notifyAllExample = new NotifyAllExample();
A1 a=new A1(notifyAllExample);
B1 b=new B1(notifyAllExample);
C1 c=new C1(notifyAllExample);
a.start();
b.start();
c.start();
}
}
class A1 extends Thread{
NotifyAllExample notifyAllExample;
A1(NotifyAllExample notifyAllExample){
this.notifyAllExample = notifyAllExample;
}
@Override
public void run() {
try{
synchronized (notifyAllExample) {
for (int i = 0; i < 100; i++) {
if(notifyAllExample.status!=1){
notifyAllExample.wait();
}
System.out.print(\"A \");
notifyAllExample.status = 2;
notifyAllExample.notifyAll();
}
}
}catch (Exception e) {
System.out.println(\"Exception 1 :\"+e.getMessage());
}
}
}
class B1 extends Thread{
NotifyAllExample notifyAllExample;
B1(NotifyAllExample notifyAllExample){
this.notifyAllExample = notifyAllExample;
}
@Override
public void run() {
try{
synchronized (notifyAllExample) {
for (int i = 0; i < 100; i++) {
if(notifyAllExample.status!=2){
notifyAllExample.wait();
}
System.out.print(\"B \");
notifyAllExample.status = 3;
notifyAllExample.notifyAll();
}
}
}catch (Exception e) {
System.out.println(\"Exception 2 :\"+e.getMessage());
}
}
}
class C1 extends Thread{
NotifyAllExample notifyAllExample;
C1(NotifyAllExample notifyAllExample){
this.notifyAllExample = notifyAllExample;
}
@Override
public void run() {
try{
synchronized (notifyAllExample) {
for (int i = 0; i < 100; i++) {
if(notifyAllExample.status!=3){
notifyAllExample.wait();
}
System.out.print(\"C \");
notifyAllExample.status = 1;
notifyAllExample.notifyAll();
}
}
}catch (Exception e) {
System.out.println(\"Exception 3 :\"+e.getMessage());
}
}
}
回答1:
Convert those IF statements to WHILE statements to get the desired behavior:
if (notifyAllExample.status != 2){
notifyAllExample.wait();
}
to
while (notifyAllExample.status != 2){
notifyAllExample.wait();
}
This will ensure that if a thread is notified, it won't go out of the while loop until the status value is what it expects.
Also, mark status as volatile so that the threads won't have a local copy.
回答2:
public class RunThreadsInOrder implements Runnable {
static int numThread = 1;
static int threadAllowedToRun = 1;
int myThreadID;
private static Object myLock = new Object();
public RunThreadsInOrder() {
this.myThreadID = numThread++;
System.out.println("Thread ID:" + myThreadID);
}
@Override
public void run() {
synchronized (myLock) {
while (myThreadID != threadAllowedToRun) {
try {
myLock.wait();
} catch (InterruptedException e) {
} catch (Exception e) {}
}
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
}
System.out.println("myThreadID is running: " + myThreadID);
myLock.notifyAll();
threadAllowedToRun++;
}
}
public static void main(String[] args) {
// TODO Auto-generated method stub
Thread t1 = new Thread(new RunThreadsInOrder());
Thread t2 = new Thread(new RunThreadsInOrder());
Thread t3 = new Thread(new RunThreadsInOrder());
Thread t4 = new Thread(new RunThreadsInOrder());
Thread t5 = new Thread(new RunThreadsInOrder());
Thread t6 = new Thread(new RunThreadsInOrder());
Thread t7 = new Thread(new RunThreadsInOrder());
t7.start();
t6.start();
t5.start();
t4.start();
t3.start();
t2.start();
t1.start();
}
}
回答3:
I was asked to write a similar program in an interview with the added condition that it should be extensible in a way that we can provide our own count of threads and they should print characters with the first thread printing 'A' and then the subsequent threads printing B, C, D and so on. Here's how I did it.
public class AlternateCharPrinter {
public static char ch = 65;
private static void createAndStartThreads(int count) {
Object lock = new Object();
for (int i = 0; i < count; i++) {
new Thread(new AlternateCharRunner((char) (65 + i), lock)).start();
}
}
public static void main(String[] args) {
createAndStartThreads(4);
}
}
class AlternateCharRunner implements Runnable {
private char ch;
private Object lock;
private static int runnerCount;
public AlternateCharRunner(char ch, Object lock) {
this.ch = ch;
this.lock = lock;
runnerCount++;
}
@Override
public void run() {
while (true) {
synchronized (lock) {
while (ch != AlternateCharPrinter.ch) {
try {
lock.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println(AlternateCharPrinter.ch++);
if (AlternateCharPrinter.ch == (65 + runnerCount)) {
AlternateCharPrinter.ch = 65;
}
lock.notifyAll();
}
}
}
}
回答4:
You need to replace
if (notifyAllExample.status!=1)
with
while (notifyAllExample.status!=1)
and same thing in the other 2 classes. If not, then as soon as the wait exits the thread continues without knowing if it is its turn.
回答5:
Replace:
if(notifyAllExample.status!=1){
notifyAllExample.wait();
}
with:
while(notifyAllExample.status!=1){
notifyAllExample.wait();
}
in all classes accordingly.
回答6:
public class Main {
public static void main(String[] args) throws IOException{
Thread t1 = new Thread(new A(), "1");
Thread t2 = new Thread(new A(), "2");
Thread t3 = new Thread(new A(), "3");
t1.start();
try{
t1.join();
}catch (Exception e){
}
t2.start();
try{
t2.join();
}catch (Exception e){
}
t3.start();
try{
t3.join();
}catch (Exception e){
}
}
}
class A implements Runnable{
public void run(){
System.out.println(Thread.currentThread().getName());
}
}
or you can use Executor Framework
public class Sequence {
int valve = 1;
public static void main(String[] args){
Sequence s = new Sequence();
ExecutorService es = Executors.newFixedThreadPool(3);
List<Runnable> rList = new ArrayList<>();
rList.add(new A(s));
rList.add(new B(s));
rList.add(new C(s));
for(int i = 0; i < rList.size(); i++){
es.submit(rList.get(i));
}
es.shutdown();
}
}
class A implements Runnable{
Sequence s;
A(Sequence s){
this.s = s;
}
public void run(){
synchronized (s) {
for (int i = 0; i < 10; i++) {
while (s.valve != 1) {
try {
s.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println("A");
s.valve = 2;
s.notifyAll();
}
}
}
}
class B implements Runnable{
Sequence s;
B(Sequence s){
this.s = s;
}
public void run() {
synchronized (s) {
for (int i = 0; i < 10; i++) {
while (s.valve != 2) {
try {
s.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println("B");
s.valve = 3;
s.notifyAll();
}
}
}
}
class C implements Runnable{
Sequence s;
C(Sequence s){
this.s = s;
}
public void run() {
synchronized (s) {
for(int i = 0; i < 10; i++) {
while (s.valve != 3) {
try {
s.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println("C");
s.valve = 1;
s.notifyAll();
}
}
}
}
In the first case the join for each thread causes the threads to wait for one another. In the second case a list stores the threads and executor executes them one after another creating 3 threads
Another way to do this is where only one runnable class is present and communication between thread is done via static variable in the main class and a variable in the runnable class
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.Executor;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
public class Seq {
int i = 1;
public static void main(String[] args){
Seq s = new Seq();
Common c1 = new Common(s, 1);
Common c2 = new Common(s, 2);
Common c3 = new Common(s, 3);
List<Runnable> l = new ArrayList<>();
l.add(c1);
l.add(c2);
l.add(c3);
ExecutorService es = Executors.newFixedThreadPool(3);
for(int i = 0; i < 3; i++){
es.submit(l.get(i));
}
es.shutdown();
}
}
class Common implements Runnable{
Seq s;
int o;
Common(Seq s, int o){
this.s = s;
this.o = o;
}
public void run(){
synchronized (s) {
for (int z = 0; z < 100; z++) {
if(s.i > 3)
s.i = 1;
while (s.i != o) {
try {
s.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println(o);
s.i++;
s.notifyAll();
}
}
}
}
回答7:
The simplest solution to solve this can be following way:
public class PrintInOrder implements Runnable {
private int valueToPrint;
private int id;
private static int turn = 1;
private static int RESET_TURN_THRESHOLD = 3;
public PrintInOrder() {
this.valueToPrint = -1;
}
public PrintInOrder(int id, int val) {
this.id = id;
this.valueToPrint = val;
}
@Override
public void run() {
while(true) {
if (turn == this.id) {
System.out.println(Thread.currentThread().getName() + "::::" + valueToPrint);
turn++;
}
if (turn > RESET_TURN_THRESHOLD) {
turn = 1;
}
}
}
public static void main(String []args) {
Thread t1 = new Thread(new PrintInOrder(1, 1));
t1.setName("THREAD-1");
t1.start();
Thread t2 = new Thread(new PrintInOrder(2, 2));
t2.setName("THREAD-2");
t2.start();
Thread t3 = new Thread(new PrintInOrder(3, 3));
t3.setName("THREAD-3");
t3.start();
}
}
/*
OUTPUT::::
THREAD-1::::1
THREAD-2::::2
THREAD-3::::3
THREAD-1::::1
THREAD-2::::2
THREAD-3::::3
THREAD-1::::1
THREAD-2::::2
THREAD-3::::3
THREAD-1::::1
THREAD-2::::2
THREAD-3::::3
THREAD-1::::1
THREAD-2::::2
THREAD-3::::3
THREAD-1::::1
THREAD-2::::2
THREAD-3::::3
...
*/
回答8:
I think it's simpler to achieve this using join. Example:
public static void main(String[] args) {
final Thread t1 = new Thread("t1") {
@Override
public void run() {
System.out.println("i am thread: " + Thread.currentThread().getName());
}
};
final Thread t2 = new Thread(t1, "t2") {
@Override
public void run() {
t1.start();
try {
t1.join();
} catch ( InterruptedException e ) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("i am thread: " + Thread.currentThread().getName());
}
};
Thread t3 = new Thread(t2, "t3") {
@Override
public void run() {
t2.start();
try {
t2.join();
} catch ( InterruptedException e ) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("i am thread: " + Thread.currentThread().getName());
}
};
t3.start();
}
回答9:
Here is my solution please try and let me know
package thread;
class SyncPrinter {
public static void main(String[] args) {
SyncPrinterAction printAction1 = new SyncPrinterAction(new int[]{1,5,9,13}, true);
SyncPrinterAction printAction2 = new SyncPrinterAction(new int[]{2,6,10,14}, true);
SyncPrinterAction printAction3 = new SyncPrinterAction(new int[]{3,7,11,15}, true);
SyncPrinterAction printAction4 = new SyncPrinterAction(new int[]{4,8,12,16}, false);
printAction1.setDependentAction(printAction4);
printAction2.setDependentAction(printAction1);
printAction3.setDependentAction(printAction2);
printAction4.setDependentAction(printAction3);
new Thread(printAction1, "T1").start();;
new Thread(printAction2, "T2").start();
new Thread(printAction3, "T3").start();
new Thread(printAction4, "T4").start();
}
}
class SyncPrinterAction implements Runnable {
private volatile boolean dependent;
private SyncPrinterAction dependentAction;
int[] data;
public void setDependentAction(SyncPrinterAction dependentAction){
this.dependentAction = dependentAction;
}
public SyncPrinterAction( int[] data, boolean dependent) {
this.data = data;
this.dependent = dependent;
}
public SyncPrinterAction( int[] data, SyncPrinterAction dependentAction, boolean dependent) {
this.dependentAction = dependentAction;
this.data = data;
this.dependent = dependent;
}
@Override
public void run() {
synchronized (this) {
for (int value : data) {
try {
while(dependentAction.isDependent())
//System.out.println("\t\t"+Thread.currentThread().getName() + " :: Waithing for dependent action to complete");
wait(100);
} catch (InterruptedException e) {
e.printStackTrace();
}
dependentAction.setDependent(true);
System.out.println(Thread.currentThread().getName() + " :: " +value);
dependent = false;
}
}
}
private void setDependent(boolean dependent) {
this.dependent = dependent;
}
private boolean isDependent() {
return dependent;
}
}
来源：https://stackoverflow.com/questions/12989397/running-3-threads-in-sequence-java