apply color function on evaluated string color

廉价感情. 提交于 2019-11-29 12:30:13

Recommended Solution:

Actually, I made the above a lot more complicated than required. A simple option would be to just form the variable name using concatenation and then evaluate it within the darken() function itself instead of using the ~"" (which outputs a String instead of a Color).

&:hover{
   @clr: "@{prefix}-@{index}";
   background-color: darken(@@clr,20%);
}

Original Answer:

Assuming I understood your query correctly, you can achieve it the below way:

@cat-1:#c40009;
@cat-2:#0009c4;

.gen-cats-filter (@index,@prefix) when (@index > 0) {
  .@{prefix}@{index}{
    background-color: ~"@{@{prefix}-@{index}}";
   &:hover{
      @clr: "@{@{prefix}-@{index}}";
      background-color: darken(color(~"`function(){return @{clr}}()`"),20%);
   }
  }
  .gen-cats-filter(@index - 1,@prefix);
}
.gen-cats-filter(2,cat); //I assumed this line was an error in your code and hence modified it.
  1. @clr: "@{@{prefix}-@{index}}"; - Just for reducing the complexity of the next line. This evaluates to "#00c409" for @cat-1.
  2. color(~"`function(){return @{clr}}()`") - Converts the string into a color value that can be used within the darken function.
  3. darken() - Darkens the color value.

CodePen Demo


With recent updates to the Less compiler, we can avoid the JS function bit also and directly write it as follows:

background-color: darken(color(@clr),20%);
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