MySQL conditional ORDER BY ASC/DESC for date column

一笑奈何 提交于 2019-11-29 10:30:52

Try this:

ORDER BY post_status ASC,
CASE post_status WHEN 'future' THEN POST_DATE END ASC,
CASE WHEN post_status <> 'future' THEN post_date END DESC

How about something like this? Select twice and union the results.

Select * from (SELECT post_status, post_date, post_title 
FROM wp_posts WHERE post_status IN ('future') 
ORDER BY post_status ASC  ) alias1  
UNION
Select * from (SELECT post_status, post_date, post_title 
FROM wp_posts WHERE post_status IN ('publish') 
ORDER BY post_status DESC ) alias2  

Try this one -

SELECT
  post_status, post_date, post_title
FROM
  wp_posts
WHERE
  post_status IN ('future', 'publish')
ORDER BY
  IF(post_status = 'future', 0, 1),
  IF(post_status = 'future', TO_DAYS(post_date), TO_DAYS(post_date) * -1);

i would use an union all, tricks in order by can't use index and is slower.

SELECT * FROM
((SELECT
  1 AS a, @rownum:=@rownum+1 B, post_status, post_date, post_title
FROM
  wp_posts, (SELECT @rownum:=0) r 
WHERE
  post_status='publish'
ORDER BY
  post_date DESC)
UNION ALL
(SELECT
  2 AS a,  @rownum:=@rownum+1 B, post_status, post_date, post_title
FROM
  wp_posts, (SELECT @rownum:=0) r2
WHERE
  post_status='future'
ORDER BY
  post_date)) ORDER BY A,B;
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