问题
As stated in spring-boot-reference:
On your application classpath (e.g. inside your jar) you can have an application.properties that provides a sensible default property value for name. When running in a new environment, an application.properties can be provided outside of your jar that overrides the name
I place a duplicated application.properties with overridden name on the same path as jar file, however when running the application with:
java -jar target/myproject-0.0.1-SNAPSHOT.jar
The name value is not overridden, it still refers to the one inside application.properties inside jar file. I also tried:
java -Dspring.config.location=/target/application.properties -jar target/myproject-0.0.1-SNAPSHOT.jar
But it does not work, please help.
Edit
When I change the current directory to target and run it, it works.
java -jar myproject-0.0.1-SNAPSHOT.jar
Why? Why cannot be outside the path and run it?
回答1:
It doesn't work because you are trying to launch the jar from another folder: spring boot looks for files/folder relative your current folder.
You can:
1) copy application.properties either in ./ or ./config/, relative to your current folder.
2) Or specify -Dspring.config.location:
$ java -Dspring.config.location=target/application.properties -jar target/myproject-0.0.1-SNAPSHOT.jar
回答2:
You spelt config as conig, should work if you spell it right.
来源：https://stackoverflow.com/questions/39427675/application-properties-outside-jar-file-how-to