How do you load a groovy file and execute it

问题

I have a jenkinsfile dropped into the root of my project and would like to pull in a groovy file for my pipeline and execute it. The only way that I\'ve been able to get this to work is to create a separate project and use the fileLoader.fromGit command. I would like to do

def pipeline = load \'groovy-file-name.groovy\'
pipeline.pipeline()

回答1:

If your Jenkinsfile and groovy file in one repository and Jenkinsfile is loaded from SCM you have to do:

Example.Groovy

def exampleMethod() {
    //do something
}

def otherExampleMethod() {
    //do something else
}
return this

JenkinsFile

node {
    def rootDir = pwd()
    def example = load "${rootDir}@script/Example.Groovy "
    example.exampleMethod()
    example.otherExampleMethod()
}

回答2:

You have to do checkout scm (or some other way of checkouting code from SCM) before doing load.

回答3:

Thanks @anton and @Krzysztof Krasori, It worked fine if I combined checkout scm and exact source file

Example.Groovy

def exampleMethod() {
    println("exampleMethod")
}

def otherExampleMethod() {
    println("otherExampleMethod")
}
return this

JenkinsFile

node {
    // Git checkout before load source the file
    checkout scm

    // To know files are checked out or not
    sh '''
        ls -lhrt
    '''

    def rootDir = pwd()
    println("Current Directory: " + rootDir)

    // point to exact source file
    def example = load "${rootDir}/Example.Groovy"

    example.exampleMethod()
    example.otherExampleMethod()
}

回答4:

If you have pipeline which loads more than one groovy file and those groovy files also share things among themselves:

JenkinsFile.groovy

def modules = [:]
pipeline {
    agent any
    stages {
        stage('test') {
            steps {
                script{
                    modules.first = load "first.groovy"
                    modules.second = load "second.groovy"
                    modules.second.init(modules.first)
                    modules.first.test1()
                    modules.second.test2()
                }
            }
        }
    }
}

first.groovy

def test1(){
    //add code for this method
}
def test2(){
    //add code for this method
}
return this

second.groovy

import groovy.transform.Field
@Field private First = null

def init(first) {
    First = first
}
def test1(){
    //add code for this method
}
def test2(){
    First.test2()
}
return this

回答5:

Very useful thread, had the same problem, solved following you.

My problem was: Jenkinsfile -> call a first.groovy -> call second.groovy

Here my solution:

Jenkinsfile

node {
  checkout scm
  //other commands if you have

  def runner = load pwd() + '/first.groovy'
  runner.whateverMethod(arg1,arg2)
}

first.groovy

def first.groovy(arg1,arg2){
  //whatever others commands

  def caller = load pwd() + '/second.groovy'
  caller.otherMethod(arg1,arg2)
}

NB: args are optional, add them if you have or leave blank.

Hope this could helps further.

来源：https://stackoverflow.com/questions/37800195/how-do-you-load-a-groovy-file-and-execute-it

标签

Jenkins

groovy

jenkins-pipeline