问题
Imagine I've got the following in a text file opened under Emacs:
some 34
word 30
another 38
thing 59
to 39
say 10
here 47
and I want to turn into this, adding 1 to every number made of 2 digits:
some 35
word 31
another 39
thing 60
to 40
say 11
here 48
(this is a short example, my actual need is on a much bigger list, not my call)
How can I do this from Emacs?
I don't mind calling some external Perl/sed/whatever magic as long as the call is made directly from Emacs and operates only on the marked region I want.
How would you automate this from Emacs?
I think the answer I'm thinking of consist in calling shell-command-on-region and replace the region by the output... But I'm not sure as to how to concretely do this.
回答1:
This can be solved by using the command query-replace-regexp (bound to C-M-%):
C-M-%
\b[0-9][0-9]\b
return
\,(1+ \#&)
The expression that follows \, would be evaluated as a Lisp expression, the result of which used as the replacement string. In the Lisp expression, \#& would be replaced by the matched string, interpreted as a number.
By default, this works on the whole document, starting from the cursor. To have this work on the region, there are several posibilities:
- If transient-mark-mode is turned on, you just need to select the region normally (using point and mark);
- If for some reason you don't like transient-mark-mode, you may use narrow-to-region to restrict the changes to a specific region: select a region using point and mark, C-x n n to narrow, perform query-replace-regexp as described above, and finally C-x n w to widen. (Thanks to Justin Smith for this hint.)
- Use the mouse to select the region.
See section Regexp Replacement of the Emacs Manual for more details.
回答2:
Emacs' column editing mode is what you need.
Activate it typing M-x cua-mode.
Go to the beginning of the rectangle (leave cursor on character
3) and press C-RET.Go to the end of the rectangle (leave cursor on character
7). You will be operating on the highlighted region.Now press M-i which increments all values in the region.
You're done.! remove dead ImageShack links
回答3:
It doesn't protect against 99->100.
(defun add-1-to-2-digits (b e)
"add 1 to every 2 digit number in the region"
(interactive "r")
(goto-char b)
(while (re-search-forward "\\b[0-9][0-9]\\b" e t)
(replace-match (number-to-string (+ 1 (string-to-int (match-string 0)))))))
Oh, and it operates on the region. If you want the entire file, then you replace b and e with (point-min) and nil.
回答4:
Moderately tested; use M-: and issue the following command:
(while (re-search-forward "\\<[0-9][0-9]\\>" nil t) (let ((x (match-string 0))) (delete-backward-char 2) (insert (format "%d" (1+ (string-to-int x))))))
回答5:
I managed to get it working in a different way using the following (my awk-fu ain't strong so it probably can be done in a simpler way):
C-u M-x shell-command-on-region RET awk '$2>=0&&$2<=99 {$2++} {print}' RET
but I lost my indentation in the process : )
Seeing all these answers, I can't help but have a lot of respect for Emacs...
来源：https://stackoverflow.com/questions/2686593/emacs-adding-1-to-every-number-made-of-2-digits-inside-a-marked-region