What is the best way to add options to a select from as a JS object with jQuery?

浪子不回头ぞ 提交于 2019-11-25 21:55:55

问题


What is the best method for adding options to a <select> from a JavaScript object using jQuery?

I\'m looking for something that I don\'t need a plugin to do, but I would also be interested in the plugins that are out there.

This is what I did:

selectValues = { \"1\": \"test 1\", \"2\": \"test 2\" };

for (key in selectValues) {
  if (typeof (selectValues[key] == \'string\') {
    $(\'#mySelect\').append(\'<option value=\"\' + key + \'\">\' + selectValues[key] + \'</option>\');
  }
}

A clean/simple solution:

This is a cleaned up and simplified version of matdumsa\'s:

$.each(selectValues, function(key, value) {
     $(\'#mySelect\')
          .append($(\'<option>\', { value : key })
          .text(value));
});

Changes from matdumsa\'s: (1) removed the close tag for the option inside append() and (2) moved the properties/attributes into an map as the second parameter of append().


回答1:


Same as other answers, in jQuery fashion:

$.each(selectValues, function(key, value) {   
     $('#mySelect')
         .append($("<option></option>")
                    .attr("value",key)
                    .text(value)); 
});



回答2:


var output = [];

$.each(selectValues, function(key, value)
{
  output.push('<option value="'+ key +'">'+ value +'</option>');
});

$('#mySelect').html(output.join(''));

In this way you "touch the DOM" only one time.

I'm not sure if the latest line can be converted into $('#mySelect').html(output.join('')) because I don't know jQuery internals (maybe it does some parsing in the html() method)




回答3:


This is slightly faster and cleaner.

var selectValues = {
  "1": "test 1",
  "2": "test 2"
};
var $mySelect = $('#mySelect');
//
$.each(selectValues, function(key, value) {
  var $option = $("<option/>", {
    value: key,
    text: value
  });
  $mySelect.append($option);
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<select id="mySelect"></select>



回答4:


jQuery

var list = $("#selectList");
$.each(items, function(index, item) {
  list.append(new Option(item.text, item.value));
});

Vanilla JavaScript

var list = document.getElementById("selectList");
for(var i in items) {
  list.add(new Option(items[i].text, items[i].value));
}



回答5:


If you don't have to support old IE versions, using the Option constructor is clearly the way to go, a readable and efficient solution:

$(new Option('myText', 'val')).appendTo('#mySelect');

It's equivalent in functionality to, but cleaner than:

$("<option></option>").attr("value", "val").text("myText")).appendTo('#mySelect');



回答6:


This looks nicer, provides readability, but is slower than other methods.

$.each(selectData, function(i, option)
{
    $("<option/>").val(option.id).text(option.title).appendTo("#selectBox");
});

If you want speed, the fastest (tested!) way is this, using array, not string concatenation, and using only one append call.

auxArr = [];
$.each(selectData, function(i, option)
{
    auxArr[i] = "<option value='" + option.id + "'>" + option.title + "</option>";
});

$('#selectBox').append(auxArr.join(''));



回答7:


@joshperry

It seems that plain .append also works as expected,

$("mySelect").append(
  $.map(selectValues, function(v,k){

    return $("<option>").val(k).text(v);
  })
);



回答8:


All of these answers seem unnecessarily complicated. All you need is:

var options = $('#mySelect').get(0).options;
$.each(selectValues, function(key, value) {
        options[options.length] = new Option(value, key);
});

That is completely cross browser compatible.




回答9:


Be forwarned... I am using jQuery Mobile 1.0b2 with PhoneGap 1.0.0 on an Android 2.2 (Cyanogen 7.0.1) phone (T-Mobile G2) and could not get the .append() method to work at all. I had to use .html() like follows:

var options;
$.each(data, function(index, object) {
    options += '<option value="' + object.id + '">' + object.stop + '</option>';
});

$('#selectMenu').html(options);



回答10:


 var output = [];
 var length = data.length;
 for(var i = 0; i < length; i++)
 {
    output[i++] = '<option value="' + data[i].start + '">' + data[i].start + '</option>';
 }

 $('#choose_schedule').get(0).innerHTML = output.join('');

I've done a few tests and this, I believe, does the job the fastest. :P




回答11:


There's an approach using the Microsoft Templating approach that's currently under proposal for inclusion into jQuery core. There's more power in using the templating so for the simplest scenario it may not be the best option. For more details see Scott Gu's post outlining the features.

First include the templating js file, available from github.

<script src="Scripts/jquery.tmpl.js" type="text/javascript" />

Next set-up a template

<script id="templateOptionItem" type="text/html">
    <option value=\'{{= Value}}\'>{{= Text}}</option>
</script>

Then with your data call the .render() method

var someData = [
    { Text: "one", Value: "1" },
    { Text: "two", Value: "2" },
    { Text: "three", Value: "3"}];

$("#templateOptionItem").render(someData).appendTo("#mySelect");

I've blogged this approach in more detail.




回答12:


I have made something like this, loading a dropdown item via Ajax. The response above is also acceptable, but it is always good to have as little DOM modification as as possible for better performance.

So rather than add each item inside a loop it is better to collect items within a loop and append it once it's completed.

$(data).each(function(){
    ... Collect items
})

Append it,

$('#select_id').append(items); 

or even better

$('#select_id').html(items);



回答13:


A compromise of sorts between the top two answers, in a "one-liner":

$.fn.append.apply($('mySelect'),
    $.map(selectValues, function(val, idx) {
        return $("<option/>")
            .val(val.key)
            .text(val.value);
    })
);

Builds up an array of Option elements using map and then appends them all to the Select at once by using apply to send each Option as a separate argument on the append function.




回答14:


The simple way is:

$('#SelectId').html("<option value='0'>select</option><option value='1'>Laguna</option>");



回答15:


Rather than repeating the same code everywhere, I would suggest it is more desirable to write your own jQuery function like:

jQuery.fn.addOption = function (key, value) {
    $(this).append($('<option>', { value: key }).text(value));
};

Then to add an option just do the following:

$('select').addOption('0', 'None');



回答16:


function populateDropdown(select, data) {   
    select.html('');   
    $.each(data, function(id, option) {   
        select.append($('<option></option>').val(option.value).html(option.name));   
    });          
}   

It works well with jQuery 1.4.1.

For complete article for using dynamic lists with ASP.NET MVC & jQuery visit: http://www.codecapers.com/post/Dynamic-Select-Lists-with-MVC-and-jQuery.aspx




回答17:


  1. $.each is slower than a for loop
  2. Each time, a DOM selection is not the best practice in loop $("#mySelect").append();

So the best solution is the following

If JSON data resp is

[
    {"id":"0001", "name":"Mr. P"},
    {"id":"0003", "name":"Mr. Q"},
    {"id":"0054", "name":"Mr. R"},
    {"id":"0061", "name":"Mr. S"}
]

use it as

var option = "";
for (i=0; i<resp.length; i++) {
    option += "<option value='" + resp[i].id + "'>" + resp[i].name + "</option>";
}
$('#mySelect').html(option);



回答18:


There's a sorting problem with this solution in Chrome (jQuery 1.7.1) (Chrome sorts object properties by name/number?) So to keep the order (yes, it's object abusing), I changed this:

optionValues0 = {"4321": "option 1", "1234": "option 2"};

to this

optionValues0 = {"1": {id: "4321", value: "option 1"}, "2": {id: "1234", value: "option 2"}};

and then the $.each will look like:

$.each(optionValues0, function(order, object) {
  key = object.id;
  value = object.value;
  $('#mySelect').append($('<option>', { value : key }).text(value));
}); 



回答19:


Yet another way of doing it:

var options = [];    
$.each(selectValues, function(key, value) {
    options.push($("<option/>", {
        value: key,
        text: value
    }));
});
$('#mySelect').append(options);



回答20:


if (data.length != 0) {
    var opts = "";
    for (i in data)
        opts += "<option value='"+data[i][value]+"'>"+data[i][text]+"</option>";

    $("#myselect").empty().append(opts);
}

This manipulates the DOM only once after first building a giant string.




回答21:


Although the previous answers are all valid answers - it might be advisable to append all these to a documentFragmnet first, then append that document fragment as an element after...

See John Resig's thoughts on the matter...

Something along the lines of:

var frag = document.createDocumentFragment();

for(item in data.Events)
{
    var option = document.createElement("option");

    option.setAttribute("value", data.Events[item].Key);
    option.innerText = data.Events[item].Value;

    frag.appendChild(option);
}
eventDrop.empty();
eventDrop.append(frag);



回答22:


You can just iterate over your json array with the following code

$('<option/>').attr("value","someValue").text("Option1").appendTo("#my-select-id");




回答23:


A jQuery plugin could be found here: http://remysharp.com/2007/01/20/auto-populating-select-boxes-using-jquery-ajax/.




回答24:


That's what I did with two-dimensional arrays: The first column is item i, add to innerHTML of the <option>. The second column is record_id i, add to the value of the <option>:

  1. PHP

    $items = $dal->get_new_items(); // Gets data from the database
    $items_arr = array();
    $i = 0;
    foreach ($items as $item)
    {
        $first_name = $item->first_name;
        $last_name = $item->last_name;
        $date = $item->date;
        $show = $first_name . " " . $last_name . ", " . $date;
        $request_id = $request->request_id;
        $items_arr[0][$i] = $show;
        $items_arr[1][$i] = $request_id;
        $i++;
    }
    
    echo json_encode($items_arr);
    
  2. JavaScript/Ajax

            function ddl_items() {
                if (window.XMLHttpRequest) {
                    // Code for Internet Explorer 7+, Firefox, Chrome, Opera, and Safari
                    xmlhttp=new XMLHttpRequest();
                }
                else{
                    // Code for Internet Explorer 6 and Internet Explorer 5
                    xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
                }
    
                xmlhttp.onreadystatechange=function() {
                if (xmlhttp.readyState==4 && xmlhttp.status==200) {
                    var arr = JSON.parse(xmlhttp.responseText);
                    var lstbx = document.getElementById('my_listbox');
    
                    for (var i=0; i<arr.length; i++) {
                        var option = new Option(arr[0][i], arr[1][i]);
                        lstbx.options.add(option);
                    }
                }
            };
    
            xmlhttp.open("GET", "Code/get_items.php?dummy_time=" + new Date().getTime() + "", true);
            xmlhttp.send();
        }
    }
    



回答25:


The JSON format:

[{
    "org_name": "Asset Management"
}, {
    "org_name": "Debt Equity Foreign services"
}, {
    "org_name": "Credit Services"
}]

And the jQuery code to populate the values to the Dropdown on Ajax success:

success: function(json) {
    var options = [];
    $('#org_category').html('');  // Set the Dropdown as Blank before new Data
    options.push('<option>-- Select Category --</option>');
    $.each(JSON.parse(json), function(i, item) {
        options.push($('<option/>',
        {
           value: item.org_name, text: item.org_name
        }));
    });
    $('#org_category').append(options);  // Set the Values to Dropdown
}



回答26:


I found that this is simple and works great.

for (var i = 0; i < array.length; i++) {
    $('#clientsList').append($("<option></option>").text(array[i].ClientName).val(array[i].ID));
};



回答27:


Using the $.map() function, you can do this in a more elegant way:

$('#mySelect').html( $.map(selectValues, function(val, key){
    return '<option value="' + val + '">'+ key + '</option>';
}).join(''));



回答28:


<!DOCTYPE html>
<html lang="en">
<head>
  <title>append selectbox using jquery</title>
  <meta charset="utf-8">
  <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

  <script type="text/javascript">
    function setprice(){
        var selectValues = { "1": "test 1", "2": "test 2" };
        $.each(selectValues, function(key, value) {   
     $('#mySelect')
         .append($("<option></option>")
                    .attr("value",key)
                    .text(value)); 
});

    }
  </script>
</head>
<body onload="setprice();">


      <select class="form-control" id="mySelect">
    <option>1</option>
    <option>2</option>
    <option>3</option>
    <option>4</option>
  </select>


</body>
</html>



回答29:


Set your HTML select id into following line below. In here mySelect is used as the id of the select element.

   var options = $("#mySelect");

then get the object which is the selectValues in this scenario and sets it to the jquery for each loop. It will use the value and text of the objects accordingly and appends it into the option selections as follows.

$.each(selectValues, function(val, text) {
            options.append(
             $('<option></option>').val(val).html(text)
          );
      });

This will display text as the option list when drop down list is selected and once a text is selected value of the selected text will be used.

Eg.

"1": "test 1", "2": "test 2",

Dropdown,

display name: test 1 -> value is 1 display name: test 2 -> value is 2




回答30:


I decided to chime in a bit.

  1. Deal with prior selected option; some browsers mess up when we append
  2. ONLY hit DOM once with the append
  3. Deal with multiple property while adding more options
  4. Show how to use an object
  5. Show how to map using an array of objects

// objects as value/desc
let selectValues = {
  "1": "test 1",
  "2": "test 2",
  "3": "test 3",
  "4": "test Four"
};
//use div here as using "select" mucks up the original selected value in "mySelect"
let opts = $("<div />");
let opt = {};
$.each(selectValues, function(value, desc) {
  opts.append($('<option />').prop("value", value).text(desc));
});
opts.find("option").appendTo('#mySelect');

// array of objects called "options" in an object
let selectValuesNew = {
  options: [{
      value: "1",
      description: "2test 1"
    },
    {
      value: "2",
      description: "2test 2",
      selected: true
    },
    {
      value: "3",
      description: "2test 3"
    },
    {
      value: "4",
      description: "2test Four"
    }
  ]
};

//use div here as using "select" mucks up the original selected value
let opts2 = $("<div />");
let opt2 = {}; //only append after adding all options
$.map(selectValuesNew.options, function(val, index) {
  opts2.append($('<option />')
    .prop("value", val.value)
    .prop("selected", val.selected)
    .text(val.description));
});
opts2.find("option").appendTo('#mySelectNew');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<select id="mySelect">
  <option value="" selected="selected">empty</option>
</select>

<select id="mySelectNew" multiple="multiple">
  <option value="" selected="selected">2empty</option>
</select>


来源:https://stackoverflow.com/questions/170986/what-is-the-best-way-to-add-options-to-a-select-from-as-a-js-object-with-jquery

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